Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Enter the equation of the circle described below. Center (3, -2), radius = 5
@bernard Where are the options at?
Do you have a picture to accompany this post?
Thank you
@bernard what is this math about??? im not understanding how i need to help you
\(\color{#0cbb34}{\text{Originally Posted by}}\) @IsabelFriedmannbells @bernard what is this math about??? im not understanding how i need to help you \(\color{#0cbb34}{\text{End of Quote}}\) If you can't help him, leave. No need to reply on a post that you have no idea how to help in.
It's geometry @isabelFriedmanbells this is Geometry
Alright, well you have to use the SF of the equation of a circle
DO you know what the general equation is?
I dont it have one TBH they jus gave me this out the blue tbh because of corona we not being taught nothing they just gave us compters and sent us home before Corona got bad bad
Okay well the equation is \[(x-h)^2+(y-k)^2=r^2\]
THank you
That's not the answer though
Center=(h,k) which equals to (3,-2)
I used r for the radius and r=5
\[(x - 3)^2 + (y - (-2))^2 = (5)^2\]
right now what we're doing is placing the values into the general equation
\[(x -3)^2 + (y + 2)^2 = 25\]
\[(x^2 - 6. + 9) + (y^2 + 4y + 4) = 25\]
i thaught you could not give direct answers
\[x^2 +y^2 - 6x + 4y +9+4 -25= 0\]
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Serenity1jacksonsl i thaught you could not give direct answers \(\color{#0cbb34}{\text{End of Quote}}\) I am not giving a direct answer
\(\color{#0cbb34}{\text{Originally Posted by}}\) @XioGonz \[x^2 +y^2 - 6x + 4y +9+4 -25= 0\] \(\color{#0cbb34}{\text{End of Quote}}\) I'll let you do the last step on your own
Okay im still working on it thank you
No problem
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