Question

Can I get some math help?

Answer 1

@AZ

Answer 2

hmm

would you say that the statement is true?

-2 < x - 7 < 2

if you add 7 on both sides, what do you get?

Answer 3

It's true

Answer 4

and there you have it

Answer 5

Can you help me with one more?

Answer 6

Sure

Answer 7

@AZ

Answer 8

It took me a few times of reading that question to understand what they're asking

We want to find all the x-values that make f(x) greater than g(x)

So here's the graph
https://www.desmos.com/calculator/ygsjv5cyj8

Answer 9

Are those answer choices that they gave you? Or are they asking you to test each one?

Answer 10

x/2 > 1 + 4/x

When they say prove it algebraically, we could try solving for x but that's just going to be messy

But I think it would be easier to just plug in random points to check which intervals are correct lol

Answer 11

It's answer choices

Answer 12

Let's solve this

x/2 > 1 + 4/x

can you write 1 + 4/x as one fraction?

basically multiply 1 by x/x

Answer 13

I 1?

Answer 14

I'm not sure what `I 1` means

What is 1 + 4/x

can you add the two to make it into one fraction?

1 is the same thing as x/x

now that they have the same denominator, you should be able to add them

Answer 15

So its 5

Answer 16

uh no?

\( 1= \dfrac{x}{x}\)

so

\( 1 + \dfrac{4}{x} = \dfrac{x}{x} + \dfrac{4}{x} \)

and you should know that when adding fractions, if the denominators are the same, then you can add the numerators

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
uh no?

\( 1= \dfrac{x}{x}\)

so

\( 1 + \dfrac{4}{x} = \dfrac{x}{x} + \dfrac{4}{x} \)

and you should know that when adding fractions, if the denominators are the same, then you can add the numerators
\(\color{#0cbb34}{\text{End of Quote}}\)
- just an idea bc. how you see this way is so confusable to @kamachavis so add the 1 to 4/x like a fraction written in this form of 1/1

\[\frac{ 1 }{ 1 } +\frac{ 4 }{ x } = ?\]