math problem
well, based off the previous answers, its got to be negative 1
lol im not sure
not sure? az explained to you the same thing several times bro
"(x, y) on the normal function for the inverse function, it would be (y, x)"
@darkknight
another way to write that would be for your function f(x) if f(\(\color{orange}{x}\)) = \(\color{red}{a}\) then for your inverse function \( f^{-1}(x)\) then \( f^{-1}(\color{red}{a}) = \color{orange}{x}\) the x-value of the inverse function is going to be the y-value of the normal function which means that the y-value of the inverse function is going to be the x-value of the normal function
im not sure
im not getting it sorry
we're looking for \( f^{-1}(1)\) 1 is the x value of the INVERSE function so that means 1 should be the y-value of the normal function so the y-value to the inverse function is going to be the x-value to the normal function so go find what the x-value is when y is 1 on your normal function
-1
\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop -1 \(\color{#0cbb34}{\text{End of Quote}}\) no
im not sue
okay, one step at a time? We're looking for \( f^{-1}(1)\) right?
\( f^{-1} (\color{red}{1})\) that 1 is the X-VALUE of the INVERSE function and we want to find out the Y-VALUE of the INVERSE function
and remember if we have (a, b) of our normal function the INVERSE function is going to be flipped and will be (b, a) so that means 1 is the X-VALUE of the INVERSE function and the Y-VALUE of the normal function
so to find the Y-VALUE of the INVERSE function we need to find the X-VALUE of the normal function and we know that the normal function has a y-value of 1 so look at your graph, what is the x-value when y is 1?
-4
so the X-VALUE of the NORMAL function is going to be the Y-VALUE of our INVERSE function and so that's your answer
the ansers -4?
yes remember we were trying to find the y-value for the inverse function we know that the x-value of the inverse function is the same as the y-value of the normal function so we found the x-value that gives us the y-value on the normal function and that x-value would be the y-value of the inverse function (x,y) inverse is (y, x)
thanks
you're welcome
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