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Mathematics 16 Online
iuytyuioiuytyuiop:

math problem

iuytyuioiuytyuiop:

1 attachment
Florisalreadytaken:

well, based off the previous answers, its got to be negative 1

iuytyuioiuytyuiop:

lol im not sure

Florisalreadytaken:

not sure? az explained to you the same thing several times bro

Florisalreadytaken:

"(x, y) on the normal function for the inverse function, it would be (y, x)"

iuytyuioiuytyuiop:

@darkknight

AZ:

another way to write that would be for your function f(x) if f(\(\color{orange}{x}\)) = \(\color{red}{a}\) then for your inverse function \( f^{-1}(x)\) then \( f^{-1}(\color{red}{a}) = \color{orange}{x}\) the x-value of the inverse function is going to be the y-value of the normal function which means that the y-value of the inverse function is going to be the x-value of the normal function

iuytyuioiuytyuiop:

im not sure

iuytyuioiuytyuiop:

im not getting it sorry

AZ:

we're looking for \( f^{-1}(1)\) 1 is the x value of the INVERSE function so that means 1 should be the y-value of the normal function so the y-value to the inverse function is going to be the x-value to the normal function so go find what the x-value is when y is 1 on your normal function

iuytyuioiuytyuiop:

-1

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop -1 \(\color{#0cbb34}{\text{End of Quote}}\) no

iuytyuioiuytyuiop:

im not sue

AZ:

okay, one step at a time? We're looking for \( f^{-1}(1)\) right?

AZ:

\( f^{-1} (\color{red}{1})\) that 1 is the X-VALUE of the INVERSE function and we want to find out the Y-VALUE of the INVERSE function

AZ:

and remember if we have (a, b) of our normal function the INVERSE function is going to be flipped and will be (b, a) so that means 1 is the X-VALUE of the INVERSE function and the Y-VALUE of the normal function

AZ:

so to find the Y-VALUE of the INVERSE function we need to find the X-VALUE of the normal function and we know that the normal function has a y-value of 1 so look at your graph, what is the x-value when y is 1?

iuytyuioiuytyuiop:

-4

AZ:

so the X-VALUE of the NORMAL function is going to be the Y-VALUE of our INVERSE function and so that's your answer

iuytyuioiuytyuiop:

the ansers -4?

AZ:

yes remember we were trying to find the y-value for the inverse function we know that the x-value of the inverse function is the same as the y-value of the normal function so we found the x-value that gives us the y-value on the normal function and that x-value would be the y-value of the inverse function (x,y) inverse is (y, x)

iuytyuioiuytyuiop:

thanks

AZ:

you're welcome

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