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Mathematics 13 Online
Aqual:

Factoring... Yay... :)

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snowflake0531:

First things first, do you want to.... explain this format? I don't do factoring like.....-that- lol

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oh

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its tic tac toe method

snowflake0531:

wat is that-

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the fromula is ax^2 + bx + c

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top left is a top middle is c top right is a*c

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middle right is a factor of a*c that adds up with the other factor to equal b

snowflake0531:

@AZ @angle i've never done something called the 'tic-tac-toe method'

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bottom right is the other factor

snowflake0531:

do you have to factor this way-

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thats how i was tought

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damn, they dipped

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im open to more methods

Angle:

sorry, had to go delete a spam post I've never learned this before but it seems similar to factoring by grouping

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yes

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ill make a template

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so the arrow shows which way the rows multiply

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a is in square 1-1

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c square 1-2

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a*c in square 1-3

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now square 2-3 and 3-3 are factors of a*c that add up to b

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once you put those there, square 2-1 * 2-2 = 2-3

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same with row 3

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then 3-1 * 2-1 = 1-1

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as with column 2

Angle:

Let me try an example and you tell me if I'm understanding your method correctly: If I had an equation: 2x^2 - x - 3 a = 2 b = -1 c = -3 Then my box would look like: |dw:1616800872750:dw|

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so, instead of -6 and 1, you would do -3 and 2 cuz -3 + 2 = -1, b

Angle:

Are you required to use this method? ;-;

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no

Angle:

good, let's try factoring by grouping instead :D

Angle:

which problem do you want to try first?

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any also, this would be ur problem

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KynxKatz:

6. Factor 2x4−13x2−45 2x^4−13x^2−45 =(2x^2+5)(x+3)(x−3)

Angle:

ohh I wasn't too far off, that would make sense

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mhm, u did good

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better than i did my first

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kynxkatz, howd u get that?

KynxKatz:

Solved it?

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yea

KynxKatz:

N just call me Kynx

KynxKatz:

That’s my first name

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ight

Angle:

Since katz is so eager to try out number 6, let's take a look at how that would look in one of your boxes 2x^4−13x^2−45 |dw:1616801365579:dw|

KynxKatz:

Imma go through the questions n solve them

KynxKatz:

Wait wht

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correct Angle

KynxKatz:

When did i give direct answers

Angle:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KynxKatz 6. Factor 2x4−13x2−45 2x^4−13x^2−45 =(2x^2+5)(x+3)(x−3) \(\color{#0cbb34}{\text{End of Quote}}\) that's a direct answer, mate

KynxKatz:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle \(\color{#0cbb34}{\text{Originally Posted by}}\) @KynxKatz 6. Factor 2x4−13x2−45 2x^4−13x^2−45 =(2x^2+5)(x+3)(x−3) \(\color{#0cbb34}{\text{End of Quote}}\) that's a direct answer, mate \(\color{#0cbb34}{\text{End of Quote}}\) Oh it u, thought it was sumone else

Aqual:

so u would make 2x^4 - 13x^2 - 45 2u^2 - 13u - 45 | u=x^2

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that allows u to make the table

KynxKatz:

I dont even have to strength to argue wit u, I’m just here to help ppl

KynxKatz:

7. Since both terms are perfect cubes, factor using the difference of cubes formula, a^3-b^3= = a^3-b^3=(a-b)(a^2+ab+b^2) where a=4x a=4x and b=1b=1 (4x−1)(16x^2+4x+1)

KynxKatz:

Srry that took so long i just got out of chemo like 1 hr ago so I’m just kinda tired

Aqual:

ight

KynxKatz:

Buh i can still continue if u want

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yes pls

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if u dont bmind

KynxKatz:

Mk

KynxKatz:

where a=2x a=2x and b=3 b=3 So (2x+3)(4x^2−6x+9) is the answer Use this formula if ur confused how i got the answer- (a−b)(a^2+ab+b^2) Since both terms are perfect cubes, factor using the difference of cubes formula, a^3−b^3

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but they arent perfect cubes though

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im confuzzled

KynxKatz:

8. Explanation: Step 1 : To factor 81x^4 −1 we can use difference of squares formula: I^2−II^2 =(I−II)(I+II) After putting I=9x^2 and II=1 , we have: 81x^4−1=(9x^2−1)(9x^2+1) Step 2 : To factor 9x^2−1 we can use difference of squares formula: After putting I=3x and II=1 , we have: 9x^2−1=(3x−1)(3x+1)

KynxKatz:

See if wht i wrote just now helps

Aqual:

i gtg now, thx tho for the help, i appreciate it very much

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