Since it'll be easier in Fahrenheit (for me)...
20*C is 68*F
and
10*C is 50*F
Firstly....
do you know what "joules" is?
441204:
looks like converting is involved
441204:
u have to convert the temperatures
KiWiPoP1:
Yeah joules is a form of energy
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KiWiPoP1:
I don't think I have to convert, since the previous practices I've done didn't need to
441204:
u gotta find when the water cooled down
441204:
subtraction
KiWiPoP1:
yeah so subtract 20-10
KiWiPoP1:
I thought that
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KiWiPoP1:
right?
QuestionCoveBot:
So... since you have to find how much joules of heat was released.
And you have 25.0 grams of water that cools from 20*C to 10*C.
A joules SI base units (you may need this) is;
\[kg⋅m2⋅s−2\]
KiWiPoP1:
ahhh, okokok
441204:
smart people lol
QuestionCoveBot:
Some more things you may need...
1×107 erg - CGS units
1W⋅s - Watt-seconds
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KiWiPoP1:
alr im just gonna do the math and see what comes out