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Chemistry 16 Online
KiWiPoP1:

I need help, ss below

KiWiPoP1:

1 attachment
QuestionCoveBot:

Since it'll be easier in Fahrenheit (for me)... 20*C is 68*F and 10*C is 50*F Firstly.... do you know what "joules" is?

441204:

looks like converting is involved

441204:

u have to convert the temperatures

KiWiPoP1:

Yeah joules is a form of energy

KiWiPoP1:

I don't think I have to convert, since the previous practices I've done didn't need to

441204:

u gotta find when the water cooled down

441204:

subtraction

KiWiPoP1:

yeah so subtract 20-10

KiWiPoP1:

I thought that

KiWiPoP1:

right?

QuestionCoveBot:

So... since you have to find how much joules of heat was released. And you have 25.0 grams of water that cools from 20*C to 10*C. A joules SI base units (you may need this) is; \[kg⋅m2⋅s−2\]

KiWiPoP1:

ahhh, okokok

441204:

smart people lol

QuestionCoveBot:

Some more things you may need... 1×107 erg - CGS units 1W⋅s - Watt-seconds

KiWiPoP1:

alr im just gonna do the math and see what comes out

KiWiPoP1:

okokok I got it now lol

KiWiPoP1:

ty

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