If the quantity 4 times x times y cubed plus 8 times x squared times y to the fifth power all over 2 times x times y squared is completely simplified to 2xayb + 4xcyd, where a, b, c, and d represent integer exponents, what is the value of a?

Question

Florisalreadytaken · Answer

$$\frac{ (4x \times y^3 + 8 \times x^2 \times y^5) }{ 2x \times y^2 }$$

Florisalreadytaken · Answer

we have got to simplify that into

$$2x^ay^b+4x^cy^d$$

Florisalreadytaken · Answer

$\color{#0cbb34}{\text{Originally Posted by}}$ @Florisalreadytaken
$$\frac{ (4x \times y^3 + 8 \times x^2 \times y^5) }{ 2x \times y^2 }$$
$\color{#0cbb34}{\text{End of Quote}}$
we can write this equation as

$$\frac{ 4xy^3}{2xy^2} + \frac{ 8x^2y^5 }{ 2xy^2 }$$

Florisalreadytaken · Answer

we get rid of the 2s at the bottom, so we have

$$\frac{2xy^3 }{ xy^2 }+ \frac{ 4x^2y^5 }{xy^2 }$$

Florisalreadytaken · Answer

thus

$$2x^{1-1}   y ^{3-2}+4x ^{2-1}y ^{5-2}$$

Florisalreadytaken · Answer

$$2x^0y^1+4x^1y^3$$

so we got it in $$2x^ay^b+4x^cy^d$$ equation form

Florisalreadytaken · Answer

by comparing them we can obv see that a=0 -- that will be your answer :D