Question

Factor completely: 2x^3 + 10x^2 + 14x + 70.

(2x2 + 14)(x + 5)
(x2 + 7)(2x + 10)
2(x3 + 5x2 + 7x + 35)
2[(x2 + 7)(x + 5)]

Answer 1

First factor the 2 out, what do you get

Answer 2

uh, idk :(

Answer 3

\[\frac{ 2x^3 }{ x } + \frac{ 10x^2 }{ 2 } + \frac{ 14x }{ 2 } + \frac{ 70 }{ 2 }\]

Answer 4

ohh

Answer 5

Oops, supposed to be 2 in teh first denominator

Answer 6

So what is it

Answer 7

x^3 + 5x^2 + 7x + 35

I think

Answer 8

So we have
\[2(x^3+5x^2+7x+35)\]
Now let's play a guessing game xd, we know that it must be
\[(x^2 + _)(x+ _ )\]
the parenthesis are a bit weird, but-

So, we have x^2 and x, which one do you think should have 5 ,which one do you think should have 7
i suggest trying both of them

Answer 9

\[(x^2 + 5x^2)(7x +35)\]

is that right.. or no??

Answer 10

Can I ask where the hell you got that from?..... lol....

Answer 11

idk

Answer 12

factoring is hard for me

Answer 13

We have (x^2 + __)(x+__)
The two _s must multiply to 35

Answer 14

oh

Answer 15

7 and 5

Answer 16

So try both of them, 5 and 7, and see which goes where, which multiplies to x^3 +5x^2 + 7x+35

Answer 17

huh?

Answer 18

FIrst try (x^2 +5)(x+7) then try (x^2 +7)(x+5)
use FOIL

And see which one multiplies to x^3 + 5x^2 + 7x+35

Answer 19

or do you want me to show you....?

Answer 20

yes please o-o

Answer 21

\[(x^2 + 5)(x+7) = x^3 + 7x^2 +5x+35\]
evidently, this does not equal \[ x^3 + 5x^2 + 7x+35\]

Answer 22

So, it's of course the second one \[(x^2 + 7)(x+5) = x^3 + 5x^2 +7x+35\]

Answer 23

ok, so its B?

Answer 24

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Isolation
\[(x^2 + 5)(x+7) = x^3 + 7x^2 +5x+35\]
evidently, this does not equal \[ x^3 + 5x^2 + 7x+35\]
\(\color{#0cbb34}{\text{End of Quote}}\)
add the 2 at the front -- you missed that my guy

Answer 25

oh right that

Answer 26

*girl xd

Answer 27

snowflake that you? -- youre quite obv

Answer 28

thanks :D

Answer 29

snow on an alt acc.. 👀

Answer 30

"xd..." "lol..."-- i only know 1 weirdo who uses them

Answer 31

; )

Answer 32

Lol,. there is 7 billion people in the world, not every genius has to be snowflake.
congrats isolation on the question :)

Answer 33

oh and btw, @carmelle , the answer is the last one!

Answer 34

not the 2nd one

Answer 35

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken
oh and btw, @carmelle , the answer is the last one!
\(\color{#0cbb34}{\text{End of Quote}}\)
oh :/

Answer 36

\[ 2 [\color{orange}{ (x^2 + 7)} \color{chocolate}{(x + 5)}]\]

isnt that what isolation just did above?

Answer 37

yeah

Answer 38

so yeah, D will be your answer 👍

Answer 39

thx

Answer 40

no prb mate