Question

math problem

Answer 1

@darkknight two points instead of one

Answer 2

f(-x+3) - 4 = f( -(x-3)) - 4
first reflect about the y axis, next shift 3 units to the right, then 4 units down

Answer 3

reflect about the y axis?

Answer 4

That looks more like a translation :o

Answer 5

reflect about the y-axis basically f(-x) reflects f(x) about the y-axis
so all points (x,y) turn into (-x, y)

Answer 6

That is how you reflect about the y-axis.

Answer 7

down 4 not 6

Answer 8

i did go 4

Answer 9

(0, 0) is where one ofthe points is, you put the translated version at (3, -6) that means you went down 6

Answer 10

The bottom corner of the original is at (0, 0). it is at (3, -6) in your transformed function

Answer 11

IT is STILL at (3, -6) look at that point

Answer 12

darkknight

Answer 13

please be patient, still incorrect, take th epoint (5, 5) from the original and perform transformations to that

Answer 14

im not sure

Answer 15

help darkknight

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) \(\color{#0cbb34}{\text{Originally Posted by}}\) darkknight
f(-x+3) - 4 = f( -(x-3)) - 4
first reflect about the y axis, next shift 3 units to the right, then 4 units down
\(\color{#0cbb34}{\text{End of Quote}}\)
darkknight
please be patient, still incorrect, take th epoint (5, 5) from the original and perform transformations to that
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 17

sorry i cant understand

Answer 18

could you explain it another way

Answer 19

could you explain it another way

Answer 20

do the exact same thing you did with the other point

Answer 21

the original function has a pint at (5,5)
if we reflect we ahve it at (-5, 5)
then 3 to the right is (-2, 5)
then 4 down (-2, 1)
The function should pass through (-2, 1)

Answer 22

(-2 ,1) not (-2, -1)

Answer 23

im not able to move up only to the side

Answer 24

dont move the other point, it was fine where it was at

Answer 25

im not able to move up

Answer 26

I can't move up

Answer 27

i can only go to the side

Answer 28

What do you want me to do about that?

Answer 29

and taht is super weird lets see

Answer 30

alright

Answer 31

@AZ

Answer 32

why you tagging other people, no one can do anything if you cant shift itup, either you are missing something or I am, so lets see if i messed up or if its just you. thank you

Answer 33

az

Answer 34

should i change the question

Answer 35

The best way to do it if you're getting confused with all of the transformations is by plugging in numbers

You have
y = f(-x + 3) - 4

so let's plug in x = 0
So what we're doing now is trying to find what the y-value is on our NEW graph when x=0 so we have to plug that in

f(-0+3) - 4
f(3) - 4


so what is f(3) on your graph?

Answer 36

im not sure

Answer 37

look at the graph of the dashed line, what is the y-value when x = 3

Answer 38

3

Answer 39

AZ u love cats to much

Answer 40

3

Answer 41

az

Answer 42

yes, f(3) = 3

so what is f(3) - 4

so basically 3 - 4 = ??

that is going to be the y-value when x = 0 on our new graph

Answer 43

-1

Answer 44

exactly so one point on your new line is going to be (0, -1)

now let's find out what the y-value is going to be when x = 2

so f(-x + 3) - 4

f(-2 + 3) - 4

what is -2 + 3 = ?

Answer 45

1

Answer 46

good

so we go frmo

f(-2 +3) - 4

and get

f(1) - 4

what is f(1) on your dashed line?

Answer 47

im not sure

Answer 48

look at your graph

f(1) means what is the y-value when x = 1

Answer 49

1

Answer 50

Good so we have

f(1) - 4
1 - 4

what is 1 - 4

and remember we had plugged in x = 2 to get this so that means this will be the y-value of x =2 on our new graph of the line

Answer 51

-3

Answer 52

so your second point is going to be (2, -3)

and I think you should be able to put those on your graph and it'll show you how the graph looks like

Answer 53

recall, the first time we used x = 0 and ended up with -1

so that first point was (0, -1) not the other way around

Answer 54

i swap points?

Answer 55

no, you accidentally plotted (-1, 0)

but the actual point is (0, -1)

Answer 56

im only able to move from the side

Answer 57

the second point was (2, -3)

why did you plot (2, -4) ?

Answer 58

i can only move to the side not up or down

Answer 59

im not able to plot 2,-3 and 0,-1

Answer 60

the first dot on top can only move to the side while the dot on the bottom can move to the side and up and down

Answer 61

okay interesting, let's try another point like

x = 5

so f(-5 + 3) - 4
f(-2) - 4
4 - 4
= 0

so another point on your new graph is (5 ,0)

can you plot (0, -1) and (5, 0)

Answer 62

so you're not able to plot (0, -1) now?

Answer 63

im not

Answer 64

should I change the uestion

Answer 65

does it give you another question to solve in place of this one?

Answer 66

yep

Answer 67

sure, tag me in your next post