math problem
@Florisalreadytaken multiply 3?
@AZ
@snowflake0531
so if you plug in x = 0 f(3x) = f(3*0) = f(0) so what is the y-value when x = 0 on the blue line? that's going to be the y-value for x = 0 on your new red line
0?
az
yes, so your first point is (0,0) now uhh if we plug in x = 1/3 we'd get f(3 * 1/3) = f(1) so for the new red line, the y-value when x = 1/3 is going to be the y-value of when x = 1 on the blue line so what is f(1) on the blue line
im not sure
1?
yes so when x = 1/3 then y = 1 on your new red graph similarly when x = 2/3 then f(3 * 2/3) = f(2) what is the y-value when x = 2 on your blue line
4
good so that means on your red line, when x = 2/3 then y = 4 and finally when you have x = 1 f(3 * 1) = f(3) what is the y-value when x = 3 on the blue line
0
so that means on your red line, when x = 1, then y = 0
im not sure where to place the points
az
are you not able to place points at like x = 1/3 and 2/3
IM able to
but im not sure how im able to find those points in the graph
it should look like something like this
az
there you go
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