Question

math problem

Answer 1

@snowflake0531

Answer 2

@AZ

Answer 3

I'm still soooooooooo confused, but if you put into desmos
x^2
y=f(2x-4)-1
f=anything
you can see that whatever you slide f equals, it always intersects (2-1)
maybe that's where your vertex should be at then ?_?

Answer 4

im not sure

Answer 5

Slide the vertex of the parabola to
(2,-1)
do you know what vertex is

Answer 6

Yea... and then.... I absolutely have no clue
I don't understand the f(2x-4)-1 thing..... lemme look through all your former questions xd

Answer 7

@Honda @Hoodmemes

Answer 8

yes? what do you need help with?

Answer 9

this uestion

Answer 10

i don't understand what you asking tho sorry

Answer 11

@darkknight

Answer 12

f(2x-4) - 1
lets now do f(2(x-2))-1
This is a little harder then the other questions, but now how would the transformations look like?
remember first horizontal dilations, then horizontal shifts, then vertical dilations, then vertical shifts

Answer 13

translation?

Answer 14

can you be more specific? how would the transformations look like

Answer 15

im not sure

Answer 16

help

Answer 17

im not sure what the transformations look like

Answer 18

That is perfectly fine, but we have gone over 10+ questions like this, any idea at all?

Answer 19

If you have none then that means you werent paying attention, I aint a puppet that repeats stuff a billion times ._.

Answer 20

so sorry not sure lol

Answer 21

its my last uestion

Answer 22

whats first step

Answer 23

darkknight

Answer 24

az

Answer 25

\(\color{#0cbb34}{\text{Originally Posted by}}\) jnlkmnjkm
so sorry not sure lol
\(\color{#0cbb34}{\text{End of Quote}}\)
life doesnt work like that, you are showing you havent learned ANYTHING. Thats not the point. I just asked about horizontal/vertical dilations and horizontal/vertical shifts. I even broke it down here
f(2x-4) - 1
lets now do f(2(x-2))-1

At this point its on you. I aint abandoning, you have to at least give an IDEA. Not just sit there and write stuff down while I am typing. Why did you say earlier that you were forllowing along if you werent?

Answer 26

sorry whats first step

Answer 27

@AZ

Answer 28

lol okay, let's just plug in numbers?

the original graph is your f(x)

the new graph is going to be f(2x-4) -1

so let's plug in some numbers to see how your new graph looks like

if we say x = 1

f(2*1 - 4) - 1

what is 2 - 4 =

and find the y-value on your dashed line at that x-value

and then subtract 1

that's going to be the y-value for when x = 1 on your new graph

Answer 29

-2

Answer 30

y value is 4

Answer 31

3?

Answer 32

yes, so one of the points on your new graph is (1, 3)

now similarly let's find out what the point on your new graph will be when x = 2

so same steps

f(2*2 - 4) - 1

what is (2*2) - 4 =

and find the y-value on your dashed line at that x-value

and then subtract 1

Answer 33

4-4=0

Answer 34

0-1=-1

Answer 35

good so another point on your new graph. So when x = 2, y = -1

let's do it one more time for when x = 3

f(3*2 - 4) - 1

what is (3*2) - 4 =

and find the y-value on your dashed line at that x-value

and then subtract 1

Answer 36

nope, the graph shouldn't be flipped

it's because the vertex is wrong

so let's find one more point so you can see how the graph will look correct

so for when x = 3

f(3*2 - 4) - 1

what is (3*2) - 4 =

and find the y-value on your dashed line at that x-value

and then subtract 1

Answer 37

3

Answer 38

3?

Answer 39

good so (3, 3)

so put the first vertex dot at (2, -1)

and the second one as (3, 3)

Answer 40

az

Answer 41

yes

Answer 42

az

Answer 43

oh, you didn't plot it correctly

it's (3, 3)

Answer 44

thanks