Question

Graphing help!

Answer 1

for

Answer 2

Let me send a pic

Answer 3

k

Answer 4

What does function mean?

Answer 5

well no direct answers but do you have a clue what the answer is

Answer 6

no Becuase I have no clue what a function is

Answer 7

So you're in trig class but you don't know what a function is?.....

Answer 8

No like I don’t know what it’s asking I lost my notebook full of my notes

Answer 9

And you can be in a trig class and not be good at math

Answer 10

Midline, reflection, max, min, should be the easiest

do you know where's the midline?

Answer 11

I think so, isn’t there where it starts or like the middle of the graph

Answer 12

And max and min yes

Answer 13

in
A sin(b(x+c)) +D
D is the midline, A is the amplitude
So, what's midline

Answer 14

is it b?

Answer 15

So -2

Answer 16

wat
in the
Asin(b(x+c))+D

D is the midline...
So look at your function.. which number is in the place of D

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie
So -2
\(\color{#0cbb34}{\text{End of Quote}}\)
no that would be amplitude

Answer 18

-1

Answer 19

yes, so there's your midline

Answer 20

I’m so sorry i struggle in this

Answer 21

And then we can know the maximum and minimum of the y-value of htis function

Do you know what amplitude is?

Answer 22

The height of the center of the line or curve

Answer 23

From the midline, how much it goes up /how much it goes down is equal, so, yea, ig that's the amplitude... don't rly get your definition

So, from -1.... we have amplitude of 2
Which means the minimum is -1-2, and the maximum is -1+2

Answer 24

What does the function mean, what is it asking?

Answer 25

So right now this is more of in the form of
Asin(x+C) + D
you kinda need to get the B out, because you need the value B to find period
I think that's what it's asking you to do.....
So we need to convert taht form to Asin(b(x+C) +D

Answer 26

oh okay

Answer 27

I think that you can change it to
-2sin(1/2(8x-pi) -1

Answer 28

Is that what it means by function tho

Answer 29

So then because period is 2pi/B
It would be 4pi as period

Answer 30

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nikkixmarie
Is that what it means by function tho
\(\color{#0cbb34}{\text{End of Quote}}\)
just put the function as -2sin(1/2(8x-pi) -1
I'm not too sure, when I did this, we didn't have a line for function....

Answer 31

Yea me either she’s teaching it in a very complicated way and gets mad when you ask for help

Answer 32

e.e

Answer 33

So would 4pi be the period for most of the functions

Answer 34

the period for this one is 4pi i think ye

Answer 35

Alright thanks

Answer 36

actually wait, hwen i graph it it's 1/2

Answer 37

yep, nevermind, the period is 1/2
But for reflection, it's yes, because if there's a negative sign, it flips

Answer 38

Okay when it’s negative though do you graph it on the opposite side of the graph

Answer 39

Or just stay on the positive side

Answer 40

What do you mean 'opposite side of the graph'

Answer 41

Let me send a pic hold on

Answer 42

It kind of just reflects over its midline

Answer 43

do I graph it where the positive radians are or the negative

Answer 44

You do know that a function continues on forever.... right?

Answer 45

clearly not. Why do u think I’m asking.

Answer 46

We have period of 1/2, which means that from the top to down, it's 1/4 pi
graph it on desmos

what do you mean.... you learn that a function continues on forever when you start learning about linear equations

Answer 47

No because my math teachers don’t teach well

Answer 48

And because it continues on forever, it doesn't really matter which point you choose to start it at, as long as its on the graph somewhere it's fine

Answer 49

I wasn’t aware.

Answer 50

i suggest using Desmos adn then comparing

Answer 51

Ok