How many grams of Al2O3 can form when 23.6 g Al react with excess Fe2O3?

Question

AZ · Answer

Hello @sonia

The first step is to write the balanced chemical reaction.

We have Al reacting with excess Fe2O3 to produce Al2O3 and Fe

$\sf Al + Fe_2O_3 \to Al_2O_3 + Fe$

Can you balance the equation first?

AZ · Answer

After you have a balanced chemical reaction, we can move on to the next steps

We need to convert from grams to moles

Can you use a periodic table and find the molar mass (atomic mass) of Al?

The molar mass tells you how many grams of that element/compound constitutes 1 mole of that substance.

So we have 23.6 grams of Al, how many moles would that be?

Keep in mind that we need to convert to moles because our chemical reaction tells us the relationship of the reactants and products in a mole-to-mole ratio