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Mathematics 18 Online
jnlkmnjkm:

math problem

jnlkmnjkm:

1 attachment
AZ:

y = a(x-h)^2 + k what is the vertex?

jnlkmnjkm:

1, -2

jnlkmnjkm:

az

AZ:

Yes y = a(x - 1)^2 - 2 we need to find 'a' first So if we look at our graph, we see there's a point on our line at (3, 2) so we plug that into our equation to solve for a 2 = a(3-1)^2 - 2 a = ??

AZ:

what is 3 - 1 =

jnlkmnjkm:

2

AZ:

2 = a(3-1)^2 - 2 so 3-1 = 2 now we get 2 = a(2)^2 - 2 what is 2^2 =

jnlkmnjkm:

4

AZ:

Now we get 2 = 4a - 2 can you solve for a?

jnlkmnjkm:

a is 1

AZ:

Good! So that means y = a(x - 1)^2 - 2 y = (x-1)^2 - 2 now what is (x-1)^2 = ?? remember \( (a-b)^2 = a^2 - 2ab + b^2\)

jnlkmnjkm:

x^2-2x+1

AZ:

good, now put it all together y = x^2 -2x +1 - 2 can you simplify it? Just add the like terms

jnlkmnjkm:

1-2

AZ:

yes, what is that?

jnlkmnjkm:

-1

AZ:

so what's your final answer?

jnlkmnjkm:

x^2-2x-1

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jnlkmnjkm x^2-2x-1 \(\color{#0cbb34}{\text{End of Quote}}\) Correct

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