Yes
y = a(x - 1)^2 - 2
we need to find 'a' first
So if we look at our graph, we see there's a point on our line at (3, 2)
so we plug that into our equation to solve for a
2 = a(3-1)^2 - 2
a = ??
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AZ:
what is 3 - 1 =
jnlkmnjkm:
2
AZ:
2 = a(3-1)^2 - 2
so 3-1 = 2
now we get
2 = a(2)^2 - 2
what is 2^2 =
jnlkmnjkm:
4
AZ:
Now we get
2 = 4a - 2
can you solve for a?
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jnlkmnjkm:
a is 1
AZ:
Good! So that means
y = a(x - 1)^2 - 2
y = (x-1)^2 - 2
now what is (x-1)^2 = ??
remember
\( (a-b)^2 = a^2 - 2ab + b^2\)
jnlkmnjkm:
x^2-2x+1
AZ:
good, now put it all together
y = x^2 -2x +1 - 2
can you simplify it? Just add the like terms
jnlkmnjkm:
1-2
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AZ:
yes, what is that?
jnlkmnjkm:
-1
AZ:
so what's your final answer?
jnlkmnjkm:
x^2-2x-1
AZ:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jnlkmnjkm
x^2-2x-1
\(\color{#0cbb34}{\text{End of Quote}}\)
Correct