@sNoWfLaKe0541 Mahth help.... Be ready for me being dumb. <3 *uploading ss*
@snowflake0531
It's the The Pythagorean Theorem. e.e Idk how to do this.
In a right triangle, where one of the angles is 90 degrees a and b ar ehte legs of the triangle, while c is the hypotenuse \[a^2 + b^2=c^2\]
In triangle a, we have the lengths of a and b, can you put it into teh equation?
\[a^2 + b^2\] a is 2, b is 4 what is it
\[2^2+4^2= 20?\]
Yep so \[20=c^2\] c equals what
ohhhhh
\[ 400?\]
20^2 = c c would equal 400 But i'm saying 20 equals c squared
\[20=c^2\] \[\sqrt20 = \sqrt c^2\]
So, \[c=\sqrt20\]
I just looked at my math book.. It shows somethng quite like this.. So my answer would be 10? or maybe 5? Or am Ijust plain stupid🤦
fhdjglKUZ<>%^E$WTr56ey7tdr6fewsdgrxzc4a plain stupid
Yeh... So uhh...
do you know how sqrt stuff works?..
It either stays as it is, or you find a perfect square in it, in this case there's a perfect square in it
\[\sqrt20 = \sqrt(4\times5) = 2\sqrt5\]
do you agree, that 4 times 5 equals 20
Yea Yea Yeaaa.
so we have \[\sqrt (4 \times 5) = \sqrt4 \times \sqrt5\] agreed?
Yeah..
so what is sqrt4
2?
yep so what is 2 times sqrt5 is 2sqrt5
\[2 \times \sqrt{5}\] uhmmmm...... uhmmmmmm.......... After a long pause she figured she may as well thinkg.. 4.472135955?
e.e i think you can make it stay at 2sqrt5 lol
Ok...
Join our real-time social learning platform and learn together with your friends!