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Florisalreadytaken:
ah ok -- so the axis of symetry would be
\[ x= -\frac{b}{2a} \]
klmjnmkj:
how to get b and a
Florisalreadytaken:
we teached you that earlier lol -- imma give you some time to remember (since you got time)
Florisalreadytaken:
snowflake do not tell him
Florisalreadytaken:
i want him to solve it
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snowflake0531:
We first have to factor this out, we have ot get this to standard form \[(x-5)^2 -1\] what does this equal, remember that \[(a-b)^2 =a^2 -2ab+b^2\]
klmjnmkj:
4 and 6?
snowflake0531:
yes
klmjnmkj:
x^2-10x+24
snowflake0531:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj
x^2-10x+24
\(\color{#0cbb34}{\text{End of Quote}}\)
Yes so from this we get (x-6)(x-4) which gets us x=6 and x=4, as you've already got above
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klmjnmkj:
alright
klmjnmkj:
whats next
klmjnmkj:
umm now
snowflake0531:
OH i didnt' even read your question, i thought youw ere just solving for the zeroes
snowflake0531:
So you had that x^2 -10x +24
a=1
b=-10
put this into -b/2a
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klmjnmkj:
-10/2 1
klmjnmkj:
i divid?
snowflake0531:
-10/2 simplifies to what
klmjnmkj:
-5
Florisalreadytaken:
do not forget we had the - at the front
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