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Mathematics 12 Online
Aaleighacruz1:

A large emerald with a mass of 982.7 grams was recently discovered in a mine. If the density of the emerald is 2.26 grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point. (6 points)

Aaleighacruz1:

please help!!!!

AZ:

Density = mass / volume mass is 982.7 density = 2.26 g/cm^3 = 2.26 g/mL so plug it in 2.26 = 982.7 / volume can you solve for volume?

Aaleighacruz1:

no

AZ:

\( 2.26 = \dfrac{982.7}{v}\) We want to get the `v` for volume all by itself what happens if you multiply `v` on both sides?

Aaleighacruz1:

but whats V?

AZ:

v is volume

Aaleighacruz1:

no but like what number?

AZ:

that's what you're solving for...

Aaleighacruz1:

so how do I multiply?

Aaleighacruz1:

or what do I multiply

AZ:

multiply the variable on both sides and so then you'll get rid of the 'v' on the right side and you'll be left with \( 2.26 \times v= \dfrac{982.7}{\cancel{v}} \times \cancel{v}\)

Aaleighacruz1:

i dont understand

AZ:

okay, instead of 'v' just imagine it's an 'x' \( 2.26 = \dfrac{982.7}{x}\) How would you solve for x?

Aaleighacruz1:

multiply?

AZ:

and what do you get?

Aaleighacruz1:

434.8?

AZ:

That's correct!

Aaleighacruz1:

thank you!

AZ:

no problem

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