Question

At the top of a 75 m hill is a car weighing 91 N. What is its potential energy?

The same car (mass of 9.3 kg) goes down the hill and at the bottom is traveling 37m/s. What is its kinetic energy ?

Answer 1

for the first one, we have to find potential energy -- we can simply do that by using the formula

\[ \text{potential energy} (U) = mgh\]

Answer 2

the formula we have to use for the 2nd question is: \( \text{kinetic energy}= \frac{1}{2} m v^2 \)

Answer 3

and we are given
\[ m=9.3kg\]
\[ v=37 m/s \]

Answer 4

just substitute the numbers, and there you go! :D

Answer 5

for the first one I got 655473 for PE

Answer 6

and for the 2nd one i got 12731.7

Answer 7

I think its right

Answer 8

they're both wrong...

Answer 9

ummm

Answer 10

are you sure the numbers you inserted in the calculator were right?

Answer 11

yeah..

Answer 12

what was i supposed to get

Answer 13

66885 for the first one?

Answer 14

344.1 for the second?

Answer 15

firstly, turn newtons into kg

Answer 16

oh

Answer 17

idk how to do this

Answer 18

hOw?

Answer 19

what even is this

Answer 20

lol am jk

Answer 21

so

\[m=9.3 kg\]
\[g=9.8m/s^2\]
\[h=75m\]
thus
\[p.e = 6835.5 J\]

Answer 22

as for the 2nd one
\[ \text{kinetic energy}= \frac{1}{2} 9.3kg \times 37m/s \; ^2 \]

Answer 23

\[ \text{kinetic energy} = \color{lightskyblue}{6365.85} J\]

Answer 24

thx