What is the volume of 40.0 grams of argon gas at STP ?

Question

AZ · Answer

Do you know

PV = nRT

and at STP that means
that you have 0 C = 273.15 K and 1 atm

and R is the ideal gas constant = 8.3145 J mol^-1 K^-1

so plug in all that you know and solve for volume

but first we have to convert 40.0 grams of argon gas to moles

Can you find the molar mass of argon gas using the periodic table?

AZ · Answer

Remember Argon gas is Ar2

so 2 times the molecular weight of argon will be the molar mass of argon gas

AZ · Answer

so 2 * 39.948 = ??

so that's the molar mass

that tells you how many grams of of argon gas is equal to 1 mole

so to find out how many moles 40 grams is

40 / molar mass = ???

AZ · Answer

and then

PV = nRT

n is the moles you just calculated
R is the gas constant and we have to use 0.0821 atm * M^-1 K^-1
T is 273.15 K
P is 1 atm

so solve for V

jaredc4 · Answer

thanks!

AZ · Answer

Did you figure it out?

If you want me to check your final answer, I'd be glad to!