Triangle ABC has vertices located at A( 0, 2), B (2, 5), and C (−1, 7). Part A: Find the length of each side of the triangle. Show your work. (4 points) Part B: Find the slope of each side of the triangle. Show your work. (3 points) Part C: Classify the triangle. Explain your reasoning.
Do you know the distance formula? \( \Large\text{Distance} = \sqrt{ (\color{cyan}{x_2} -\color{red}{x_1})^2 + (\color{green}{y_2} - \color{orange}{y_1)}^2 } \) where you have two points \(\Large (\color{red}{x_1}, \color{orange}{y_1})\) and \(\Large (\color{cyan}{x_2}, \color{green}{y_2})\)
yes
We need to calculate the length of three sides so we have to find the distance between A \((\color{red}{0}, \color{orange}{2})\) and B \((\color{cyan}{2}, \color{green}{5})\) AB = ?? B \((\color{red}{2}, \color{orange}{5})\) and C \((\color{cyan}{-1}, \color{green}{7})\) BC = ?? A \((\color{red}{0}, \color{orange}{2})\) and C \((\color{cyan}{-1}, \color{green}{7})\) AC = ??
We can do one at a time? What's the distance between A and B? A \((\color{red}{0}, \color{orange}{2})\) and B \((\color{cyan}{2}, \color{green}{5})\)
Use the distance formula
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