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Mathematics 22 Online
Scarlet23:

Find each arc length. Round to the nearest hundredth.

Scarlet23:

xXGoldenMinaceXx:

@AZ .......i sommon you

xXGoldenMinaceXx:

i thought about it n i think im wrong im not shure

surjithayer:

what is the measure of arc PS?

Scarlet23:

its looks to be the same as RS so 16?

surjithayer:

no, i am asking about PS. do you know?

Scarlet23:

no

surjithayer:

\[180-16=164^\circ\]

Florisalreadytaken:

ok, we have to use the arc length formula, but be4 we do that, we have to find what PTS is -- so were given a straight angle separated into 2 sections -- the \(16^o\) one, and \(x^o\). -- we know that that is \( 180^o \) , so subtract \( 16^o \) from that -- ^^ that dude did it above, so we get \( 164^o \)

Scarlet23:

PTS is 164

Florisalreadytaken:

\[ s=2\pi \color{chocolate}{r} (\frac{\color{lightskyblue}{\theta}} {360}) \] where \[ \color{chocolate}{r}=11 \] and \[ \color{lightskyblue}{\theta} = 164^o \]

Scarlet23:

31.46?

Florisalreadytaken:

close, but not really -- it would be \( 31.49 \)

1 attachment
Scarlet23:

so that would be answer for PS?

Florisalreadytaken:

\( \overset\frown{PS}=31.49^o \), yes

Scarlet23:

thank you

Florisalreadytaken:

you got it!

surjithayer:

\[\theta=164^\circ=164\times \frac{ \pi }{ 180}=\frac{ 41 }{ 45} \pi radians\] \[l=r \theta =11\times \frac{ 41 }{ 45 } \pi= \frac{ 451 }{ 45}\pi \approx 31.49 ~ft\]

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