Mathematics
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klmjnmkj:
math problem
5 years ago
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klmjnmkj:
5 years ago
klmjnmkj:
2 * 0.5 ?
5 years ago
klmjnmkj:
@Florisalreadytaken
5 years ago
klmjnmkj:
@minustempo
5 years ago
Florisalreadytaken:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj
2 * 0.5 ?
\(\color{#0cbb34}{\text{End of Quote}}\)
what?
5 years ago
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Florisalreadytaken:
this is what its stated
\[ y \propto x^2 \]
We must convert that, into an equation by adding the constant of variation (k).
\[y=k \times x^2 = kx^2\]
where
\( y=2\)
\(x=0.5\)
5 years ago
klmjnmkj:
2/0.5^2
5 years ago
Florisalreadytaken:
yes -- and what would that be?
5 years ago
klmjnmkj:
8
5 years ago
Florisalreadytaken:
yes! so \( k=8 \)
thus,
\[ y=8 x^2 \]
5 years ago
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klmjnmkj:
5 years ago
klmjnmkj:
you checked if x is a z lol
5 years ago
Florisalreadytaken:
Oh my bad! it varies inversely! i thought it varied directly!
5 years ago
Florisalreadytaken:
lets do it from the beginning lol!
\[ y=\frac{k}{x^2} \]
5 years ago
klmjnmkj:
2/0.5^2?
5 years ago
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Florisalreadytaken:
no -- \( 2=\frac{k}{0.5^2}
\)
5 years ago
klmjnmkj:
k/0,5^2
5 years ago
klmjnmkj:
2 * 0.5^2 ?
5 years ago
Florisalreadytaken:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj
2 * 0.5^2 ?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes!
5 years ago
klmjnmkj:
0.5/x
5 years ago
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Florisalreadytaken:
no, just 0.5 -- we did the x part already
5 years ago
Florisalreadytaken:
thats why:
\[ y=\frac{0.5}{x^2} \]
5 years ago
klmjnmkj:
5 years ago
Florisalreadytaken:
nooo
5 years ago
klmjnmkj:
5 years ago
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Florisalreadytaken:
yes! haha
5 years ago
Florisalreadytaken:
youre welcome! :D
5 years ago
klmjnmkj:
thanks
5 years ago