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Mathematics 15 Online
klmjnmkj:

math problem

klmjnmkj:

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klmjnmkj:

2 * 0.5 ?

klmjnmkj:

@Florisalreadytaken

klmjnmkj:

@minustempo

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj 2 * 0.5 ? \(\color{#0cbb34}{\text{End of Quote}}\) what?

Florisalreadytaken:

this is what its stated \[ y \propto x^2 \] We must convert that, into an equation by adding the constant of variation (k). \[y=k \times x^2 = kx^2\] where \( y=2\) \(x=0.5\)

klmjnmkj:

2/0.5^2

Florisalreadytaken:

yes -- and what would that be?

klmjnmkj:

8

Florisalreadytaken:

yes! so \( k=8 \) thus, \[ y=8 x^2 \]

klmjnmkj:

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klmjnmkj:

you checked if x is a z lol

Florisalreadytaken:

Oh my bad! it varies inversely! i thought it varied directly!

Florisalreadytaken:

lets do it from the beginning lol! \[ y=\frac{k}{x^2} \]

klmjnmkj:

2/0.5^2?

Florisalreadytaken:

no -- \( 2=\frac{k}{0.5^2} \)

klmjnmkj:

k/0,5^2

klmjnmkj:

2 * 0.5^2 ?

Florisalreadytaken:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj 2 * 0.5^2 ? \(\color{#0cbb34}{\text{End of Quote}}\) yes!

klmjnmkj:

0.5/x

Florisalreadytaken:

no, just 0.5 -- we did the x part already

Florisalreadytaken:

thats why: \[ y=\frac{0.5}{x^2} \]

klmjnmkj:

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Florisalreadytaken:

nooo

klmjnmkj:

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Florisalreadytaken:

yes! haha

Florisalreadytaken:

youre welcome! :D

klmjnmkj:

thanks

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