Question

In a experiment, it was found that the population of a bacterial colony doubles every 10 minutes. The following function represents the number of bacteria in the colony after x minutes.
3(2)^x/10

Which statements are true?

- The expression (1,024)^x reveals the approximate rate of increase in the population of the bacterial colony per hour.

- The expression (0.93)^x reveals the approximate rate of increase in the population of the bacterial colony per minute.

- The expression (1.07)^x reveals the approximate rate of increase in the population of the bacterial colony per minute.

- The expression 2^x/10 reveals that the population of the bacterial colony increases by 100% every 10 minutes.

- The expression (1,024)^x reveals the approximate rate of increase in the population of the bacterial colony per minute.

- The expression 2^x/10 reveals that the population of the bacterial colony increases by 200% every 10 minutes.

Answer 1

what do you think solution can be?

Answer 2

let us check
\[3(2)^{\frac{x}{10}}\]
when x=0.\[population ~of ~bacteria~=3(2)^0=3\]
when x=10\[population=3(2)^{\frac{x}{10}}=3(2)^{\frac{10}{10}}=3(2)^1=6\]
increase in population=6-3=3
\[percentage~increase= \frac{ increase~of~poulation }{ original~population} \times ~100\]
plug the values and find the solution.