Ask your own question, for FREE!
Mathematics 12 Online
snowflake0531:

ss vvv

Joe348:

what do you think it is?

snowflake0531:

@joe348 wrote:
what do you think it is?
If you can't help, don't comment. If you can help, just... help because asking what do you think it is doesn't help <.<

Joe348:

@snowflake0531 wrote:
@joe348 wrote:
what do you think it is?
If you can't help, don't comment. If you can help, just... help because asking what do you think it is doesn't help <.<
ok sorry..

Joe348:

so this is what i did cos(0) divided by 1+sin(0) plus tan(0)(1+sin(0) over by the same as cos

Joe348:

I think it is D btw

snowflake0531:

@tranquility please help?

jhonyy9:

like a first step rewrite tan theta = sin theta/cos theta

snowflake0531:

\[\frac{ tanx }{ 1+sinx } + \frac{ sinx }{ cosx }\]

snowflake0531:

oops i meant cosx in the top first fraction

jhonyy9:

ok make the common denominator and multiplie by what need the first ans second numerator

jhonyy9:

what will get ?

snowflake0531:

\[\frac{ \cos^2x + \sin^2x+sinx }{ cosx +sinxcosx }\]

jhonyy9:

ok in numerator the sum of the first two terms equal how many ?

snowflake0531:

tan^2 x?

jhonyy9:

no i mean in numerator the sum of the first two terms = ?

jhonyy9:

sin^2 +cos^2 = ?

jhonyy9:

the fundamental formula of trigonometry

jhonyy9:

= 1

jhonyy9:

in this way in numerator what will get ?

snowflake0531:

sorry i was afk for a second

jhonyy9:

@snowflake0531 wrote:
\[\frac{ \cos^2x + \sin^2x+sinx }{ cosx +sinxcosx }\]
look here

jhonyy9:

is to late i like finich it

jhonyy9:

do you see what result up and bottom ?

jhonyy9:

= (1+sinx)/cosx(1+sinx) = ?

snowflake0531:

1/cosx, so it's d thank youuuuuuuuuuuuuuuuuuuuu

jhonyy9:

anytime cya

snowflake0531:

byeee

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!