ss vvv
what do you think it is?
so this is what i did cos(0) divided by 1+sin(0) plus tan(0)(1+sin(0) over by the same as cos
I think it is D btw
@tranquility please help?
like a first step rewrite tan theta = sin theta/cos theta
\[\frac{ tanx }{ 1+sinx } + \frac{ sinx }{ cosx }\]
oops i meant cosx in the top first fraction
ok make the common denominator and multiplie by what need the first ans second numerator
what will get ?
\[\frac{ \cos^2x + \sin^2x+sinx }{ cosx +sinxcosx }\]
ok in numerator the sum of the first two terms equal how many ?
tan^2 x?
no i mean in numerator the sum of the first two terms = ?
sin^2 +cos^2 = ?
the fundamental formula of trigonometry
= 1
in this way in numerator what will get ?
sorry i was afk for a second
is to late i like finich it
do you see what result up and bottom ?
= (1+sinx)/cosx(1+sinx) = ?
1/cosx, so it's d thank youuuuuuuuuuuuuuuuuuuuu
anytime cya
byeee
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