Question

find the quotient of the complex numbers. express your answer in trigonometric form z1=12(cos(320)+isin(320) z2= 4(cos(80)+isin(80)

Answer 1

https://questioncove.com/study#/updates/514362e0e4b04cdfc581bfb1

Answer 2

Which means that we have
z1=12(cos(320)+isin(320)
z2= 4(cos(80)+isin(80)
12/4 =3
320-80=240
320-80=240
So, if those are the choices, in the link above, it would be D
3(cos(240))+isin(240)

Answer 3

thank you

Answer 4

\[z_{1}=12e^{320 \iota}\]
\[z _{2}=4 e^{80 \iota}\]
\[\frac{ z_{1} }{ z_{2 }}=\frac{ 12 e ^{320 \iota} }{ 4 e^{80 \iota } }=3 e^{320 \ \iota-80 \ \iota}=3e^{240 \ \iota }\]
\[=3 (cos 240 +\iota sin 240)\]