Question

help ss below

Answer 1

@AZ

Answer 2

Hey!

To add fractions (to get it into a single fraction), you have to find the GCF of the denominators because remember you need to have the same denominator to be able to add them

The simplest way would be to multiply each fraction (top and bottom) with the denominator of the other fraction

but that wouldn't be the simplest form

so we have
\(6ab^2\)

and
\(9a^2b\)

what is the GCF of 6 and 9?
and of a and a^2?
and of b^2 and b?

we're going to then want to multiply each fraction by something to make the denominator into that greatest common factor

Answer 3

so 6 and 9 are 3 and then a and a^2 is a and b^2 and b is b?

Answer 4

oh oops, I said GCF but I meant LCM

my bad

we want the least common multiple

so the smallest multiple that's common between 6 and 9

and a and a^2

and b^2 and b

Answer 5

oh i see so
6 and 9 is 18
a and a^2 is a^2 and
b^2 and b is b^2

Answer 6

yup!!

So the LCM is

18a^2b^2

so that means we need to multiply the first fraction (and the second one) by something to get the denominator to both be 18a^2b^2

can you do that?

Answer 7

the fist one u multply by 3a the secong by 2b

Answer 8

6ab^2 * something = 18a^2 b^2

and you multiply the numerator with the same 'something'

and then for the other fraction

9a^2b * something else = 18a^2b^2
and you multiply the numerator of this with that same 'something else'

Answer 9

you got it!

Answer 10

k so then i apply that to the top and get (2+a)3a=6a+3a^2
and also (9-b)2b=18b-2b^2
so
6a+3a^2+18b-2b^2/18a^2*2b^2

Answer 11

is that the answer or could it be simplfied?

Answer 12

\(\dfrac{3a(2+a)}{18a^2b^2} + \dfrac{2b(9-b)}{18a^2b^2}\)

\(\dfrac{6a +3a^2}{18a^2b^2} + \dfrac{18b-2b^2}{18a^2b^2}\)

\(\dfrac{6a +3a^2+18b-2b^2}{18a^2b^2}\)

yeah that's as much as we can simplify it

Answer 13

cool thx

Answer 14

you're welcome!