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Mathematics 8 Online
klmjnmkj:

math problem

Cjfrfr:

what do u need help with

klmjnmkj:

1 attachment
klmjnmkj:

@AZ

Cjfrfr:

ion dont know tht lmaoooooo

Cjfrfr:

@AZ

Cjfrfr:

@AZ

Cjfrfr:

...

AZ:

So to vertically stretch or compress, you would have to change the 'c' in \( y = ce^{ax} + b\) vertical compressions would have to be a number between 0 and 1 vertical stretch would mean that c is greater than 1 and since it's a vertical compression by a factor of 6, that means... you're dividing by 6 so 1/6 does that make sense?

Cjfrfr:

@az wrote:
So to vertically stretch or compress, you would have to change the 'c' in \( y = ce^{ax} + b\) vertical compressions would have to be a number between 0 and 1 vertical stretch would mean that c is greater than 1 and since it's a vertical compression by a factor of 6, that means... you're dividing by 6 so 1/6 does that make sense?
u smart🤟

klmjnmkj:

0.16

AZ:

if you're reflecting across the y-axis you need to replace x with `-x` and if you're shifting the graph up by 1 unit, what would your 'b' be?

AZ:

@klmjnmkj wrote:
0.16
I'm sure you can just keep it as 1/6 since that would be more precise

klmjnmkj:

-b

AZ:

no we're shifting UP by 1 unit

klmjnmkj:

+b

AZ:

+ b means you're shifting up by 'b' units but what if you're shifting up by '1' unit?

klmjnmkj:

+1

AZ:

there we go so can you put everything I told you together?

klmjnmkj:

1/6e^-x+1

AZ:

you got it!

klmjnmkj:

1 attachment
AZ:

hmm, maybe try 6 instead of 1/6 maybe I overthought the vertical compression/stretching thing

klmjnmkj:

1 attachment
AZ:

oh wait your original equation is \( y = e^{-5x}\)

AZ:

you lost the 5

wassuplol:

Toast yall talkin bout why yall so smart

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