Question

math problem

Answer 1

@AZ

Answer 2

\(y = a (b)^x\)

when x = 0, you have y = -7

when x = 1, you have y = -14

can you figure out what 'a' and 'b' is

remember that b^0 = 1
so when x = 0, then what is the 'a' value?

Answer 3

im not sure about the a value

Answer 4

when x = 0, y = -7

\(-7 = a \times b^0\)

anything to the power of 0 is going to be 1
so b^0 is 1

so what is a??

Answer 5

-7

Answer 6

there you go, so now we know that 'a' is

let's figure out b

\(\Large y = -7(b^x)\)

so when x = 1, then b =-14

and you should know that anything to the power of 1, is going to be that number itself

so b^1 = b

so replace x with 1, and y with -14
solve for b

Answer 7

98

Answer 8

how?

Answer 9

-7 times -14

Answer 10

no...

-14 = -7 * b

how do you find b?

Answer 11

2

Answer 12

there you go

Answer 13

the anser is 2

Answer 14

no, the value of 'a' is -7

and the value of 'b' is 2

so put it all together

Answer 15

-7(2)^x

Answer 16

ta-da