Pick a two-digit number greater than 25. Rewrite your two-digit number as a difference of two numbers. Show how to use the identity (x − y)^2 = x^2 − 2xy + y^2 to square your number without using a calculator.
The number is 30.
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carmelle:
@AZ can you help?
carmelle:
@darkknight can you help?
carmelle:
@snowflake0531 can u help :)
snowflake0531:
Well choose 2 numbers _-_ = 30
Florisalreadytaken:
the point of this is to find what the square of that number would be, without using a calculator
ok, so you picked 30
lets rewrite that as a difference of 2 numbers -- so that would be \(35-5\)
where
\( x=35 \)
\( y=5 \)
substitute that into this
\((x − y)^2 = x^2 − 2xy + y^2\)
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Florisalreadytaken:
actually, whats the point of this?😂
Florisalreadytaken:
you would use that calculator to find \( 35^2 \) anyway
carmelle:
ok
\[(35 - 5)^{2} = 35^2 - 2(35)(5) + y^2\]
carmelle:
5^2 *
carmelle:
@florisalreadytaken wrote:
you would use that calculator to find \( 35^2 \) anyway
fr smh
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carmelle:
1225 - 350 + 25
is this correct?
Florisalreadytaken:
ok, sp by doing the whole thing in 1 go, it will be:
\( (x − y)^2 = x^2 − 2xy + y^2 \)
\( (35 - 5)^{2} = 35^2 - 2(35)(5) + 5^2 \)
\( 900 =1225 -350 + 25 \)
\( 900= 900\)
carmelle:
thank you sooo much :D
Florisalreadytaken:
you got it :D
AZ:
@florisalreadytaken wrote:
actually, whats the point of this?😂
@florisalreadytaken wrote:
you would use that calculator to find \( 35^2 \) anyway
Perhaps if you used simpler numbers like
30^2 = (40-10)^2
then you wouldn't have to use a calculator
but the purpose of this assignment seems to be just teaching you the identity and not necessarily the most efficient way of finding the square of a number