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\[\frac{ 4x+8 }{ 2 } \le12\]
Multiply 2 by each side first
it has been so long since i have done these, i forgot how to work them lol
@snowflake0531 wrote:
Multiply 2 by each side first
\[\frac{ 4x+8 }{ 2 }(2) \le 12(2)\]
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see thts what confuses me
Ignore the sign -_-
you multiply the 4x and the 8 by 2?
Well, since 4x+8, that whole thing, is over 2, but then multiplies by 2, it is left with ust 4x+8
bruh, how
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wdym how when you divide somethind by a number, but then multiply it by hte same thing, it's left with just the number \[\frac{ x }{ y } (y) = x\]
ooh lol, i was thinking something else. i tend to over think stuff. srry
Okay so what do you get
@snowflake0531 wrote:
\[\frac{ 4x+8 }{ 2 }(2) \le 12(2)\]
so then it is just. 4x+8<24? and u work it?
Yep, like that, and find x, although remember the sign
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loll thank you, it makes sense now.
kkay yw~
@haydenwh wrote:
so then it is just. 4x+8<24? and u work it?
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