math problem
@snowflake0531
@florisalreadytaken
exponential function form \(f(x) = a^x\)
is it not \[ f(x) = a \times b^x\] ?
whos right
following the one Andreas suggested, it will be a very long and hard t understand explanation lol -- so lets go with mine -- lowe me a moment to write it down
alright
\[y=a(b)^x\]
so, an exponential function is in the form of: \( y = a \times b^x \) we are given: \[ x=2 \; ; \; y=-12 \] and \[ x=3 \; ; \; y=-24 \] for the first one we have: \[ -12= a \times b^2 \] \[ a= \frac{-12}{b^2} \] looking at the first equation, we plug ^ that in for \(a\): \[ y=(\frac{-12}{b^2}) \times b^x \]
I simplify y=(-12/b^2)*b^x
1
nono. substitue the coordinates of the 2nd point, and then solve for b: \[ -24=(\frac{-12}{b^2}) \times b^3 \] do the math
im not sure
b = 2
ahh my whole latex went in the bin๐ญ๐ -- but yes, \( b=2 \)
do you remember \( a= \frac{-12}{b^2} \)? now we can fully solve for a. \[ a= \frac{-12}{2^2} \] \[ \underline{a=-3} \]
so we have \[ a=\color{lightskyblue}{-3} \] and \[ b=\color{tomato}{2} \]
what? noooo
plugging that info in the formula, we get \[ \Large f(x) = \color{tomato}{2} \times \color{lightskyblue}{ -3}^x \] \[ \updownarrow \] \[ \Large f(x) = \color{tomato}{2} \times \color{lightskyblue}{( -3)}^x \]
thanks
you got it!
oh, maybe the \( \times \) sign is not necessary
that doesnt make sense :\ -- and you missed the exponential \(x\) in your answer
lol
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