Help, Please!! 6th-grade math... (Picture down under this in the comments)
We just learned yesterday to do it with fractions, I know you do BxWxH but after that I'm kinda stuck
Does someone know how to do this? Its due tonight and I have Cross Country at 3
Well since no one is deciding to help you, Imma do it smh. This is for number 10. \[B*W*H\]Since it's a cube, all sides are 1/2 units
ok
So the equation would be: \[\frac{ 1 }{ 2 }*\frac{ 1 }{ 2 }*\frac{ 1 }{ 2 }\]What is 1/2 * 1/2 * 1/2 then?
1/8th?
Yes. So now for Part B of 10 (the 1/3 unit). Just like before: \[\frac{ 1 }{ 3 }*\frac{ 1 }{ 3 }*\frac{ 1 }{ 3 }\]What is that then?
ok, one sec
1/27th?
Yes. So for Part A on 10: You have 1/8 units Part B: You have 1/27 units The cube you are filling has a volume of 8 cubic units.
ok
And so- we started with 1/2 unit for Part A 1/3 unit for Part B The rectangular prism you are filling is 8 cubic units- How many times does 1/2 go into 8?
16
Yes. And how many times does 1/3 go into 8?
24
Yes. Now it states in question 10: "How many more of the cubes with 1/3 unit side lengths than cubes with 1/2 unite side lengths are needed to fill the prism?" It's just asking for the difference between 24 and 16. Just subtract those two. \[24-16\]
8
Yes. So there is your answer for number 10: 8 Now for number 11. I'll just explain why: It takes more cubes with lengths 1/3 to fill the prism because 1/3 is smaller than 1/2.
ok, thanks
You're welcome
So your rectangular prism has a volume of 8 You then calculated that the volume of a cube with side lengths 1/2 would be 1/8 and that the volume of a cube with side lengths 1/3 would be 1/27 Now you're filling up this rectangular prism with as many cubes with side lengths 1/2 and then you empty it out and fill it up with the 1/3 side length cubes
So to find out how many cubes would fit into your rectangular prism, you have to divide not by the side lengths but by the volumes this is where you went wrong earlier
so how many cubes with side length of 1/2 can fit into the prism? The volume of a cube with side length 1/2 is 1/8 as you found earlier \( 8 \div \dfrac{1}{8} = ?\) remember \( a\div \dfrac{b}{c} = a \times \dfrac{c}{b}\) so essentially \( 8 \div \dfrac{1}{8} = 8\times 8 = ??\) What is 8 * 8 = ?? That's how many cubes with side length of 1/2 can fit in the prism
Similarly, for the cube with side length of 1/3. It has a volume of 1/27 like you found earlier So to find out how many of those cubes would fit in \( 8 \div \dfrac{1}{27}= ?\) So what is 8 * 27 = ?
And then find the difference between those two numbers you calculate That's how many more cubes with sides of 1/3 there are compared to the cube with sides of 1/2
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