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Mathematics 21 Online
jknkjkjnjjjkl:

math problem

jknkjkjnjjjkl:

jknkjkjnjjjkl:

@florisalreadytaken

kittybasil:

Well, firstly - do you know how to convert to the natural log \(e\)?

Florisalreadytaken:

what your teacher wants you to do is, to do it in this way: \[\log _{a} b=\log b / \log a\] where \[ a=7 \] \[ b=t \]

kittybasil:

Converstion tips (Below is an example. This is NOT solving your question, it is an example!)

1 attachment
kittybasil:

oops I spelled conversion wrong. But do you get what to do so far? @jknkjkjnjjjkl

jknkjkjnjjjkl:

log(b)/log7

kittybasil:

Actually, no - they explicitly mentioned the natural log, which is \(\large{log_{e}}\) or \(\ln\) So instead we'd be calculating like this:\[\frac{\ln b}{\ln7}=?\]By the way, idk how many decimal places they want you to round to, so...

Florisalreadytaken:

@jknkjkjnjjjkl wrote:
log(b)/log7
look above -- what did i meantion about \( b=? \)

jknkjkjnjjjkl:

t

Florisalreadytaken:

then plug that in!

kittybasil:

Oops, did it backwards. Flip that fraction...\[\frac{\ln7}{\ln t}=?\]This should be what you have.

kittybasil:

btw it's not log, it's ln or log e

jknkjkjnjjjkl:

n^6/b

kittybasil:

...wait what?

Florisalreadytaken:

@florisalreadytaken wrote:
what your teacher wants you to do is, to do it in this way: [color= inherit;][/color]\[\log _{a} b=\log b / \log a\] where [color= inherit;][/color]\[ a=7 \] [color= inherit;][/color]\[ b=t \]
lapsus😂 -- i didnt notice in the second part -- its \( \ln \) instead of \( \log\)

Florisalreadytaken:

let me make it clear once again THE RIGHT WAY. \[ \log _{a} b=\frac{\ln b }{ \ln a} \] \[ a=7 \] \ thus, we get this: \[ \Large \log _{7} t=\frac{\ln t }{ \ln 7} \]

Florisalreadytaken:

why did it delete it? \[ b=t \]

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