math problem
we've done like 5 of these already! give it a shot to solve it urself, and i will explain it to u in just a bit. busy momentally.
ah -- i will solve this, and then go so, the form we want ti to be is \[ y=a(b)^x \] lets solve for a first -- the coordinates of the 1st point are: \[ (y,exponential \ \ x) \Rightarrow (1,-20) \] plugging that info in the formula, we get: \[ -20=a(b)^1 \] \[ a=?? \]
-20/b
@kittybasil
dude f(x) is the same thing as trying to find y........subtract 80-20 to get the y.........u make stuff hard and confusing.....and stop with the usless comments
-20/b
a=-20/b?
guys
b= ??
4
positive 4, or negative 4?
positive 4
awesome! so we have \[ b=4 \] lets find a \[ a= -\frac{20}{b} \] \[ a= -\frac{20}{4} \] \[ a= ? \]
-5
correct! so we have \[ a=-5 \] \[ b=4 \] plug that in this formula \[ y=a(b)^x \]
-20^x
nono, do not do anything with it -- leave it in \( y=a(b)^x \) form
y=-5(4)^x
There you go! remember from your previous posts, that we got it wrong, just because the way you inserted it was not as your teacher set it up? to make sure we get it correctly, it should be: \[ \Large f(x)=-5 \cdot 4^{x} \] so basically just take the brackets off haha.
thanks
you got it!
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