Question

A 22.22g substance needs 7,000 J of heat to increase the temperature by 16.6 degrees C. What is the object’s specific heat?

Answer 1

@allison

Answer 2

@441204

Answer 3

Yeah?

Answer 4

Good lord

Answer 5

I think multiplication is involved

Answer 6

lmao

Answer 7

prob

Answer 8

Hey adov u ever heard of copy and paste?

Answer 9

yeah why

Answer 10

@0mega

Answer 11

U should uhhhh use it cuzzo lol

Answer 12

there is none answers for that on the internet

Answer 13

I'm not good with chem

Answer 14

@extrinix

Answer 15

I mean its jus lookin for the specific heat honestly adov i dont know 🤔

Answer 16

https://questioncove.com/study#/updates/5f640a5e675ea39cf8d04000

Answer 17

The link is for who you should ping

Answer 18

thanks i was looking for that

Answer 19

@mrmudd183

Answer 20

Sorry I'm late to the party.
Specific heat is the "number of Calories required to raise the temperature of 1 gram of a substance by 1 Celsius degree"
1 Joule is about 0.24 Calories, so 7000 Joules is about 1673 Calories.
So, it takes 1673 Calories to raise the temperature of 22.22 grams of the substance by 16.6 degrees Celsius. That relationship can be expressed as 1673Calories/22.22grams/16.6degreesCelsius. But we want the Calories/gram/degreeCelcius, so we have to do some conversions:
If we divide 1673 by 22.22, we can calculate that it would take 75.30 Calories to raise the temperature of 1 gram of the substance by 16.6 degrees Celsius.
If we divide the energy again by 16.6, we can calculate that it would take 4.54 Calories to raise the temperature of 1 gram of the substance by 1 degree Celsius.
So, the Specific Heat of the substance is 4.54 Calories/gram/degree Celsius

Answer 21

dang thanks you good in like everything lmao