math help ss below
@AZ
@ihelpuuhelpme
interesting question the product of two nonzero numbers is equal to twice the sum You have the first half correct a*b But the second half is wrong What is twice the sum? You have (a+b)/2 That would be half of the sum
2a+2b=ab?
yes but let's just keep it as ab = 2(a+b)
So now the question wants us to find the sum of their reciprocals The reciprocal of a is 1/a The reciprocal of b is 1/b 1/a + 1/b would be the sum I saw you made some very nice useful tutorials on adding fractions :)) Can you make those two fractions have a similar denominator and add them together?
oh so (a+b)/ab=a+b?
I'm not sure where you got the `= a+b` part from
but 1/a + 1/b = (a+b)/ab that much is definitely correct
well i thought 1/a+1/b=sum
i probably misread it?
no, the original question says that the product of two numbers equals to twice the sum and we got this expression a * b = 2(a+b) You just have to store this in the back of your head for now but we do come back to use this The question then asks you, what is the sum of the reciprocals and you told me that 1/a + 1/b (which is the sum of the reciprocals) can be rewritten as (a+b)/ab Do you understand/agree so far?
yes. what should the other side be?
so that's what we're trying to find but remember that expression we stored in the back of our minds? take a look at it and re-arrange it ab = 2(a+b) what do you get if you divide ab on both sides and then multiply by 1/2 on both sides
so 1/2= (a+b)/ab?
Bingo and so what is the sum of their reciprocals if 1/a + 1/b = (a+b)/ab = ?? you just found the value!
1/2!
Ta-da!! Well done :D
thanks :)
You're welcome :)
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