Question

help math

Answer 1

For some of these, you could use the good old Pythagorean theorem to find the distance between the points.
For example, between W and X, you go to the right 4 units and down 2 units. We could imaging a right triangle with legs 4 and 2; this lets us find the length of the third "leg", which is also the distance between W and X.
4^2+2^2 = c^2; 16+4 = c^2; 20 = c^2; c would be between 4 and 5, around 4.5

It's just like Florisalreadytaken explained in their image. Very nice notes, I might add.

Answer 2

what about the first one

Answer 3

would it be 4.47

Answer 4

For WX, it's probably easiest to use Pythagorean theorem, like in the picture.
And your calculations are spot-on! 4.47 it is

Answer 5

with it all together it would be a deimal with .47 right

Answer 6

so 14.47

Answer 7

Yup, that's what you get when you add all the sides together!

Answer 8

thanks so much guys