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Mathematics 5 Online
Joe348:

how do I solve for X?

Joe348:

Joe348:

I got 7.3 but idk how to explain it

josiahcantcount:

b=c2﹣a2=11.22﹣8.52≈7.29315

Joe348:

what

Joe348:

how would I type that in tho?

kittybasil:

that's the Pythagorean theorem:\[a^2+b^2=c^2\] a and b are the legs and c is the hypotenuse (longest side) so it would be this, basically\[x^2+8.5^2=11.2^2\]and solve as such

kittybasil:

the formatting just got a little bugged up there

Joe348:

Thank you and its fine c:

kittybasil:

what's a c colon?

Joe348:

lol a smiley face yk c: ;-; (:

kittybasil:

yk? Thanks for the tip

Joe348:

lol no problem

Joe348:

wait are you sure its 11.2?

kittybasil:

Also not sure what's fine - are you good or should I keep going? (yes it's 11.2 for hypotenuse \(c\))

Joe348:

idk its just somehow I got 7.3 instead but idk how

Joe348:

oh wait no im solving for x-?

kittybasil:

the answer isn't 11.2, that's the hypotenuse if you're looking for \(x\) you have to solve for it based on what josiah and I have written

Joe348:

okay but tbh he made no sense

kittybasil:

he just didn't format this right lol\[x^2+8.5^2=11.2^2\]then it would be\(11.2^2-8.5^2\)and he basically solved directly

Joe348:

Okay thank you

kittybasil:

do you know how to get that or should I continue? (it's okay if you don't btw, everyone starts somewhere)

Joe348:

Yes I got it, then find the square root of that number

Joe348:

I actually need help with one similar to this

kittybasil:

Ok cool :-) just so you can be sure though\[11.2^2-8.5^2=x^2\]\[x=\sqrt{11.2^2-8.5^2}=\sqrt{125.44-72.25}=\sqrt{53.19}\approx7.29315...\]

kittybasil:

which is basically what he wrote earlier

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