Yes, it should turn out to something like this;
\[2\sqrt{3}\]
QuestionCoveBot:
How...\[2\sqrt{3}\]?
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QuestionCoveBot:
That's not correct.
Imagine:
Example answer.
QuestionCoveBot:
Oh. ._.
QuestionCoveBot:
\[\sqrt{48}\]So we start with the prime factorization. Do you know what the prime factorization of 48 is?
Imagine:
Sorry, Umm 16*3?
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QuestionCoveBot:
Oh that works too. ._.
Well go with.. \[2^4*3\]...instead.
Apply the radical rule:
\[\sqrt{ab}=\sqrt{a}\sqrt{b}\]Fill it in. (A is 2^4 and B is 3).
\[\sqrt{2^4*3}=\sqrt{2^4}\]
Yea imagine's right qcb xd
Putting it all the way to 2^4 is just an extra step
it would be better to just do \[\sqrt48 = \sqrt(16 \times 3) = \sqrt16 \times \sqrt3 = 4 \times \sqrt3\]
Imagine:
Ah, so it would be
\[4\sqrt{3}\]
Thank you QCB for the other explanation. XD
Thank you Snow for the explanation. =)
snowflake0531:
yw xd
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QuestionCoveBot:
Yes. Correct. and yw
Imagine:
Another one?
snowflake0531:
sure another post tho
jhonyy9:
@questioncovebot wrote:
Oh that works too. ._.
Well go with.. \[2^4*3\]...instead.
Apply the radical rule:
\[\sqrt{ab}=\sqrt{a}\sqrt{b}\]Fill it in. (A is 2^4 and B is 3).
\[\sqrt{2^4*3}=\sqrt{2^4}\]