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not sure about 9 and 14 @AZ
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another way to write it would be \(\Large\sqrt[3]{x} = x^{\frac{1}{3}}\)
\(\Large\log_a b^c = c ~\log_a b\)
so \[ \frac{1}{3} ln ~x\]
see, how hard was that?
e.e i forgot about fraction exponents *facepalm
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the second one, you have to remember \(\Large \log (ab) = \log a + \log b\)
And then for 14 just 5log10 + log sqrty ?
and then use
@az wrote:
\(\Large\log_a b^c = c ~\log_a b\)
also log 10 = 1 and what can we write log sqrt(y) as? hint: think about what we did to #9
5 + 1/2 log y
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ta-da
tyty xdd
ywyw xdd
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