Question

geometric series

Answer 1

you can just plug in i = 0

and then 1, 2, and 3

and then add up all the values

Answer 2

Oki thank you

Answer 3

What did you get as your final answer?

Answer 4

ok so i did \[\sum_{}^{3} i=0^5 (\frac{ -2 }{ 3}) ^i= 5 ^1- \frac{(-2/3)^4 }\]

Answer 5

basically i did \[ 3 (\frac{ 65 }{ 81 }) = \frac{ 65 }{ 27 } \] as my answer

Answer 6

5 - 10/3 + 20/9 - 40/27

hmm yeah that's the correct final answer