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Mathematics 9 Online
Joe348:

Math help

Joe348:

AZ:

|dw:1620656085016:dw|

Joe348:

Okay thanks

AZ:

Let me know what you get but that's the formula it's half of the difference of the intercepted arcs

Joe348:

Okay I will

Joe348:

Okay tbh I actually have no clue... I'm not good with word problems

Florisalreadytaken:

bro... just look at the drawing \[m\angle U= \frac{1}{2} \left( m\overset{\huge\frown}{SW} - m\overset{\huge\frown}{TV} \right)\] \[ m\angle U=(6x-19)^\circ \] \[ m\overset{\huge\frown}{SW} =(12x-5)^\circ \] \[ m\overset{\huge\frown}{TV} = (2x+7)^\circ \] thus, \[ (6x-19)^\circ= \frac{1}{2} \left[ (12x-5)^\circ - (2x+7)^\circ \right] (\cdot 2) \] \[ 2(6x-19)^\circ= \left[ (12x-5)^\circ - (2x+7)^\circ \right] \] \[ (12x-19)^\circ=\left[ (12x-5)^\circ - (2x+7)^\circ \right] \] just continue solving for x

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Joe348:

okay where did you get msw-mtv?

AZ:

it's based on the formula

newdawn1:

i think those are the formulas where the numbers go

Florisalreadytaken:

lapsus-- the last one is \( (12x-38)^\circ=\left[ (12x-5)^\circ - (2x+7)^\circ \right] \)

newdawn1:

so he showed the formula first then replaced it with numbers

Joe348:

okay

Joe348:

Okay I did that... 13 right?

AZ:

yup

newdawn1:

good job

Joe348:

Thank you c:

Florisalreadytaken:

my whole latex went to the bin... but yeah \( x=13 \) remember? \( m\overset{\huge\frown}{SW} =(12x-5)^\circ \) plug 13 in for x, and you will have an answer

Joe348:

so 12x13 minus 5?

Florisalreadytaken:

positive

Joe348:

okay thanks flor

Joe348:

and az

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