math help

Question

math help

RomMosher · Answer

attachment

crispyrat · Answer

lets do pemdas
first the paratheses
(1-(-3)^2)--> do the exponents the do 1-

Florisalreadytaken · Answer

$$    {2 \cdot(-5) }  +   \left(  1-(-3)^{2}   \right)^2 $$
$$ \color{lightskyblue}{10} +(1-\color{tomato}{9})^2   $$
$$ -10+(-8)^2    $$
$$ -10+64  $$
find the sum of the 2 numbers, and were fully done evaluating it.

supie · Answer

$(2)\times(−5)+\color{red}{(−1−}\color{lime}{(−3)^2}\color{red}{)}^2$
first, I would solve $2\times-5$ 
when you're solving that, remember that a positive times a negative equals a positive, $(+)\times(-)=(+)$

then after that solve what is inside of the parenthesis, $\color{red}{(−1−}\color{lime}{(−3)^2}\color{red}{)}$ 
you can start by solving $(-3)^2$ 
what is 3^2= ?

Florisalreadytaken · Answer

first of all, the way youre explaining it is confusing.

@supie wrote:

when you're solving that, remember that a positive times a negative equals a positive, $(+)\times(-)=(+)$

$(-)\times(-)=(+)$ * and bro its the same thing -- do not redo a thing, which was already explained.

supie · Answer

@florisalreadytaken wrote:

first of all, the way youre explaining it is confusing.

@supie wrote:

when you're solving that, remember that a positive times a negative equals a positive, $(+)\times(-)=(+)$

$(-)\times(-)=(+)$ * and bro its the same thing -- do not redo a thing, which was already explained.

no, there aren't two negatives when i'm solving $2\times(-5)$, I actually meant $(+)\times(-)=(-)$ the way im explaning is confusing? you didn't even explain at all nobody explained what I wrote and you're incorrect 😂

@florisalreadytaken wrote:

$$ {2 \cdot(-5) } + \left( 1-(-3)^{2} \right)^2 $$ $$ \color{lightskyblue}{10} +(1-\color{tomato}{9})^2 $$ $$ -10+(-8)^2 $$ $$ -10+64 $$ find the sum of the 2 numbers, and were fully done evaluating it.

you didn't explain any of your steps (like i said before) so i dont know what you did wrong to get where you got and you're supposed to guide the user to the answer rather than do the whole thing except the last part or they would only know how to do the last part, adding (in this case) especially if you're not gonna explain anything just something i've learned through my months of being a nub anyways your math is wrong also, like i said before im not so sure what you did to get your wrong answer but it looks like you first did $2\times(-5)$and got 10 but $\bf(+)\times(-)=(-)$ so it would be negative 10 not just 10 so you're already incorrect then somehow you simplified $(1-(-3)^2$ to $(1-9)$ ? im assuming you did $-3^2=3\times3=9$ which is wrong, it should be negative 9 but somehow you ended up with $10+(1-9)$ Then you subtracted 1-9=-8 and got $-10+(-8)^2$, somehow the 10 turned negative or maybe you forgot it the first time either way if you forgot or whatever the case is, it's still incorrect anyways, you did -8^2=64 ? that's also incorrect, $-8^2=\color{red}{-}64$ most, if not, everything you did was incorrect

Florisalreadytaken · Answer

oh i have time lol -- lemme clear this up

@supie wrote:

you didn't explain any of your steps (like i said before) so i dont know what you did wrong to get where you got and you're supposed to guide the user to the answer rather than do the whole thing except the last part or they would only know how to do the last part, adding (in this case) especially if you're not gonna explain anything just something i've learned through my months of being a nub

there was this one teacher who, most of the time, did not explain what he did when solving equations -- when I asked him why he didnt explain what he did while solving equations and expressions most of the time, he said that he wants us to guess AND find out what he did -- plus, thats easy math.

@supie wrote:

it looks like you first did $2\times(-5)$and got 10 but $\bf(+)\times(-)=(-)$ so it would be negative 10 not just 10 so you're already incorrect

i just missed the $-$ when doing the colouring little one -- you can see i kept it correct after that. -- as for the precious replies, i was not clear what you meant -- thats why i put the double negatives in.

@supie wrote:

then somehow you simplified $(1-(-3)^2$ to $(1-9)$ ? im assuming you did [color= inherit;][/color]$-3^2=3\times3=9$ which is wrong, it should be negative 9

its $ (-3) \times (-3) $ and not $ 3 \times 3 $

@supie wrote:

you did $-8^2=64$ ?

what? i never did that? what are you talking about -- why did you turn the expression into an equation?

@supie wrote:

most, if not, everything you did was incorrect

am curious to see what the correct answers would be according to you lol -- there is no other possible solution, thats why im intrigued. $ \underset{\huge\smile}{. .} $

supie · Answer

Yeah it's kinda confusing with all the negatives, 
nicely done c:

RomMosher · Answer

But I finished that yesterday..... That's why it's closed

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