A gardener wants the three rosebushes in her garden to be watered by a rotating water sprinkler. The gardener draws a diagram of the garden using a grid in which each unit represents 1 ft. The rosebushes are at (1, 3), (5, 11), and (11, 4). She wants to position the sprinkler at a point equidistant from each rosebush. Where should the gardener place the sprinkler? What equation describes the boundary of the circular region that the sprinkler will cover? P.S: I saw some answers from other websites but the explanations are quite vague-- I prefer explanations over answers (It's okay if you'll just going to list down the formula I can use in a corresponding manner. Man, I just want to sleep. Thank u in advance!)
Hello! (for future references please refrain from using inappropriate words) Lets go through this problem step by step
Thank you! really sorry, was just really in a bad mood since I've tried understanding it but nothing really comes to mind.
It's all good (:
First step - We set up the problem \[(1 - h)^2 + (3 - k)^2 = (5 - h)^2 + (11 - k)^2\]
There are various of ways to solve it, but I'm not sure what method I should use though.
Ohh okay2
Okay so what is the next step?
We seperate into parts and our outcome should be- \[1 - 2h + 9 - 6k = 25 - 10h + 121 - 22k\]
Oh! So you just need to expand the binomial? (like make it into a trinomial)
The next step is to combine like terms right?
Yes
\[10 - 2h - 6k = 146 - 10h - 22k\]
Then we divide both sides of the equation by 2 - \[10 - 2h - 6k = 146 - 10h - 22k\]
ooh, i have another question.
We're still not done here. ;O
oh sorry hehe, ill ask after.
Lol, Do you know what the next step is?
\[5h - h + 11k - 3k = 73 - 5\] \[4h + 8k = 68\] \[h + 2k = 17\]
\[h = 17 - 2k\]
But there's even more to this problem-
oh no--
Lol, but it's alright we can do this \[h = 17 - 2k\] ^ What do we get now?
the value of h?
\[h = (17 * 19 - 213) / 19\]
Now what is 17*19
323
then we subtract it with 213
Alright now we plug that in - \[h = (323 - 213) / 19\]
Leaves you with?
110/19
or 5.8
Yes Correct, and now-
For (1,3) (11,4)
\[(1 - h)^2 + (3 - k)^2 = (11 - h)^2 + (4 - k)^2\]
Now what do you do next?
just like we did before, we expand the binomial and if im correct i think it'd look like this- 1 - 2h + 9 - 6k = 121 - 22h + 16 - 8k
Yes exactly
And then- \[10 - 2h - 6k = 137 - 22h - 8k\]
then, combine like terms: 20h + 2k = 127
Yes correct
\[20 * (17 - 2k) + 2k = 127\]
340 - 40k + 2k = 127
\[340 - 40k + 2k = 127\] \[-38k + 340 - 127 = 0\] \[213 = 38k\] \[k = 213/38\] \[Y = 5.6\]
Okay, so you're answer is? :D
Your*
h= 5.8 k= 5.6
sooo, that's the coordinates of the center
The boundary equation is- (x - 110/19)² + (y - 213/38)² = Square root 29.73 or (x -5.8)² + (y -5.6)² =Square root 29.73.
and to get the boundary smth, we just substitute the value of h and k to the equation of the circle formula
OOOhhh
Lol, Good Job!!
Now we're done here (:
Thank you sm for teaching me!! :)))
Feel free to leave a medal XD
wahahhaha idk how, but thanks! ive just recently join. You earned yourself another fan!
Lol It's all good, the medals are right over here
And thanks for the fan!
hi again, uhh u awake? Forgot I have to ask a question. How come when we solved for the binomial (to make it into trinomial) (1−h)^2+(3−k)^2=(5−h)^2+(11−k)^2, we didn't get a variable with an exponent after?
like shouldnt we get h^2 when we solved for (1-h)^2? Thanks in advance!
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