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Mathematics 17 Online
plsHelpImBadAtMath:

A gardener wants the three rosebushes in her garden to be watered by a rotating water sprinkler. The gardener draws a diagram of the garden using a grid in which each unit represents 1 ft. The rosebushes are at (1, 3), (5, 11), and (11, 4). She wants to position the sprinkler at a point equidistant from each rosebush. Where should the gardener place the sprinkler? What equation describes the boundary of the circular region that the sprinkler will cover? P.S: I saw some answers from other websites but the explanations are quite vague-- I prefer explanations over answers (It's okay if you'll just going to list down the formula I can use in a corresponding manner. Man, I just want to sleep. Thank u in advance!)

XioGonz:

Hello! (for future references please refrain from using inappropriate words) Lets go through this problem step by step

plsHelpImBadAtMath:

Thank you! really sorry, was just really in a bad mood since I've tried understanding it but nothing really comes to mind.

XioGonz:

It's all good (:

XioGonz:

First step - We set up the problem \[(1 - h)^2 + (3 - k)^2 = (5 - h)^2 + (11 - k)^2\]

plsHelpImBadAtMath:

There are various of ways to solve it, but I'm not sure what method I should use though.

plsHelpImBadAtMath:

Ohh okay2

XioGonz:

Okay so what is the next step?

XioGonz:

We seperate into parts and our outcome should be- \[1 - 2h + 9 - 6k = 25 - 10h + 121 - 22k\]

plsHelpImBadAtMath:

Oh! So you just need to expand the binomial? (like make it into a trinomial)

plsHelpImBadAtMath:

The next step is to combine like terms right?

XioGonz:

Yes

XioGonz:

\[10 - 2h - 6k = 146 - 10h - 22k\]

XioGonz:

Then we divide both sides of the equation by 2 - \[10 - 2h - 6k = 146 - 10h - 22k\]

plsHelpImBadAtMath:

ooh, i have another question.

XioGonz:

We're still not done here. ;O

plsHelpImBadAtMath:

oh sorry hehe, ill ask after.

XioGonz:

Lol, Do you know what the next step is?

XioGonz:

\[5h - h + 11k - 3k = 73 - 5\] \[4h + 8k = 68\] \[h + 2k = 17\]

XioGonz:

\[h = 17 - 2k\]

XioGonz:

But there's even more to this problem-

plsHelpImBadAtMath:

oh no--

XioGonz:

Lol, but it's alright we can do this \[h = 17 - 2k\] ^ What do we get now?

plsHelpImBadAtMath:

the value of h?

XioGonz:

\[h = (17 * 19 - 213) / 19\]

XioGonz:

Now what is 17*19

plsHelpImBadAtMath:

323

plsHelpImBadAtMath:

then we subtract it with 213

XioGonz:

Alright now we plug that in - \[h = (323 - 213) / 19\]

XioGonz:

Leaves you with?

plsHelpImBadAtMath:

110/19

plsHelpImBadAtMath:

or 5.8

XioGonz:

Yes Correct, and now-

XioGonz:

For (1,3) (11,4)

XioGonz:

\[(1 - h)^2 + (3 - k)^2 = (11 - h)^2 + (4 - k)^2\]

XioGonz:

Now what do you do next?

plsHelpImBadAtMath:

just like we did before, we expand the binomial and if im correct i think it'd look like this- 1 - 2h + 9 - 6k = 121 - 22h + 16 - 8k

XioGonz:

Yes exactly

XioGonz:

And then- \[10 - 2h - 6k = 137 - 22h - 8k\]

plsHelpImBadAtMath:

then, combine like terms: 20h + 2k = 127

XioGonz:

Yes correct

XioGonz:

\[20 * (17 - 2k) + 2k = 127\]

plsHelpImBadAtMath:

340 - 40k + 2k = 127

XioGonz:

\[340 - 40k + 2k = 127\] \[-38k + 340 - 127 = 0\] \[213 = 38k\] \[k = 213/38\] \[Y = 5.6\]

XioGonz:

Okay, so you're answer is? :D

XioGonz:

Your*

plsHelpImBadAtMath:

h= 5.8 k= 5.6

plsHelpImBadAtMath:

sooo, that's the coordinates of the center

XioGonz:

The boundary equation is- (x - 110/19)² + (y - 213/38)² = Square root 29.73 or (x -5.8)² + (y -5.6)² =Square root 29.73.

plsHelpImBadAtMath:

and to get the boundary smth, we just substitute the value of h and k to the equation of the circle formula

plsHelpImBadAtMath:

OOOhhh

XioGonz:

Lol, Good Job!!

XioGonz:

Now we're done here (:

plsHelpImBadAtMath:

Thank you sm for teaching me!! :)))

XioGonz:

Feel free to leave a medal XD

plsHelpImBadAtMath:

wahahhaha idk how, but thanks! ive just recently join. You earned yourself another fan!

XioGonz:

Lol It's all good, the medals are right over here

1 attachment
XioGonz:

And thanks for the fan!

plsHelpImBadAtMath:

hi again, uhh u awake? Forgot I have to ask a question. How come when we solved for the binomial (to make it into trinomial) (1−h)^2+(3−k)^2=(5−h)^2+(11−k)^2, we didn't get a variable with an exponent after?

plsHelpImBadAtMath:

like shouldnt we get h^2 when we solved for (1-h)^2? Thanks in advance!

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