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Mathematics 5 Online
MrsHero:

help ss down below

MrsHero:

1 attachment
itsmehjay:

you have to find the common factor for each number. see if there is a number that both the numerator and the denominator can be easily divided by

Astrid1:

Let's put it this way. \[\frac{ 4 }{ 20} Can~Become~ \frac{ 2 }{ 5}\] This means it can be reduced and hasn't yet. \[\frac{ 6 }{ 9 } Can~become~\frac{ 3 }{ 3 } \] Which can be whole but it hasn't been reduced. \[\frac{ 5 }{ 13} 13~ Can't~be~reduced~\] Because it's as low as it can go ^^. \[ \frac{ 14 }{ 21} \to \frac{ 7 }{ 11 } \] Can be reduced but hasn't yet. So from what we're left with, what do you think the answer is?

Astrid1:

I didn't mean to add the 13 2 times on the 3rd one xd

MrsHero:

A??

Astrid1:

Nope.

itsmehjay:

4/20 can be easily divided again to make a new fraction 4 and 20 can both be divided by 2, therefore it's not in it's simplest form

MrsHero:

i really think its B

itsmehjay:

nope... 6 and 9 can be divided by 3 \[6\div3=2\] \[9\div3=3\]

snowflake0531:

Just look at it this way, in which fraction, do the numerators and denominators not have a single common factor besides for 1?

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