Question

ss below please help

Answer 1

the formula of the circle is \( (x-a)² + (y-b)² = c² \)

we're given \( (x-4)^2+(y-1)^2=1 \)

\(1\) is the same as \( 1^2 \) -- nothing changes

so we have \( (x-4)^2+(y-1)^2=1^2 \)

a is the coordinate for the x acis ; b is the coordinate for the y axis ; c is the radi :
\[ (x-a)^2 + (y-b)^2 = c^2 \Rightarrow (x-4)^2+(y-1)^2=1^2 \]

so what is a, b, and c?

Answer 2

what? do you just do 1^2

Answer 3

yeah it doesnt indicate anything

\( 1 \times 1 = 1 \) right?

Answer 4

yeah

Answer 5

first lets look at a
\[ (x-a)^2 \Rightarrow (x-(+4))^2\]so what is a ( the x axis coordinate)?

Answer 6

im confused wym what is it

Answer 7

what is `a` ??? look
\[ (x-\color{lightskyblue}a)^2 \Rightarrow (x-(\color{lightskyblue}{+4}))^2 \]

Answer 8

4

Answer 9

sweet!

so what is `b`?
\[ (y-\color{lightskyblue}b)^2 \Rightarrow (y-(\color{lightskyblue}{+1}))^2 \]

Answer 10

1

Answer 11

noooo is not its homework

Answer 12

god i need to tell my teacher to fix the homework pages

Answer 13

yes so
\[ x=4 \]
\[ y=1 \]
radius is left -- we said that radius is c from the main formula right?
\[ \color{lightskyblue}c^2=\color{lightskyblue}1^2 \]
that said, what is the radius of that circle?

Answer 14

its just 1

Answer 15

yes!
so we can see that the center of it is \( (4 , 1) \) and the radi is \( 1 \)

Answer 16

thx