Pyramid A is a square pyramid with a base side length of 8 inches and a height of 9 inches. Pyramid B has a volume of 2,880 in3. How many times bigger is the volume of pyramid B than pyramid A? 15 32 54 75
ok so what do you know so far
can u round up to something close and divide and subtract?
Well first we have to find the volume of Pyramid A with the Volume formula of a square pyramid
Pyramid volume formula: lwh/3
8 x 8 x 9 ÷ 3
192 / 3
The basic formula of any pyramid is \(\frac{1}{3}\) multiplied by base area \(B\) and height \(h\). Since your base is a square, all you have to do is square the length to get the base area. So that's sixty-four square inches of base area. The height is 9 inches, so we now input these two values into the formula:\[V=\frac{1}{3}Bh=\frac{1}{3}(64\text{ in}^2)(9\text{ in})=64\cdot3\text{ in}^3=192\text{ in}^3\]
Wait. Where did you get \(192\div3\) from?
If you did \(8\cdot8\cdot9\div3\) in left-to-right order it'd be \(64\cdot9\div3=576\div3=192\) This is generally why I write out the fractional format so there's no extra numbers being used on accident. Hope that helps! • Cheers, Kitt
Yeah i messed that up i meant 8 x 8 x 9 / 3 Then we would get 576 /3 =192
Yep. Thanks for working with me! You did great :) Cheers!
So we put 2880 /192 And i got 15 as the final answer is that correct
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