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Mathematics 7 Online
crispyrat:

math help ss below @AZ

crispyrat:

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AZ:

speed = distance / time His distance remains the same, but depending on how fast or how slow he's walking, then the time changes. We want to know the distance he walked so we can rearrange the formula distance = speed * time if we call his original speed as x then it takes him 't' miles to walk that distance 'd' d = x * t but if he walks 1/2 mph faster, he takes 4/5 the time Remember, it's the same distance so d = (x + 1/2) * (4/5 * t) and if he walks 1/2 mph slower, it takes him 2.5 hours longer It's the same distance d = (x - 1/2) * (t + 2.5) We have three equations and so we just need to solve for x and t and the distance would be x * t

crispyrat:

so if d=x*t then xt=(x + 1/2) * (4/5 * t) xt=(x - 1/2) * (t + 2.5) then what should i do?

AZ:

Look at that first equation when you set it equal to each other xt=(x + 1/2) * (4/5 * t) you can divide 't' on both sides so now just solve for 'x'

crispyrat:

oh ok so i can have x=4/5x+0.4 1/5x=0.4 so x=2?

AZ:

Yup and then we can just plug in x = 2 in the next equation and solve for 't' xt=(x - 1/2) * (t + 2.5) so 2t=(2 - 1/2) * (t + 2.5)

crispyrat:

ok so 2t=3/2t+15/4 so 1/2t=15/4 so t is 30/4??

AZ:

yeah, or 15/2 if you want to simplify it and so x = 2 t = 15/2 or 7.5 and remember the original speed and time was x and t d = x * t so what is the distance?

crispyrat:

2*15/2 so d=15

AZ:

There you go :)

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