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Mathematics 20 Online
kekeman:

More math: https://snipboard.io/viE326.jpg

Extrinix:

Seeing that \(\overline{AD}\) is parallel to \(\overline{BC}\), we'll look for a \(180^\circ\) now, to find \(\angle A\) we need to find out which angles are similar, \(\angle A\) is similar to \(\angle D\) and \(\angle B\) is similar to \(\angle C\), now the only choice for \(\angle A\) is this: \(\angle A + \angle B = 180\) but \((x+16)+(x) = 180\) is not an option, so look for the similar angle, \(\angle C\) now we can create the equation for \(\angle A + \angle C = 180\) this would be, \((x+16)+(6x-4) = 180\) so, answer choice 1 would be your answer.

darkknight:

You got the correct answer but I would like to disagree with your reasoning, We can not assume that the lines are parallel, a property is that opposite angles of a quadrilateral are supplementary which then you can use that to prove all that above. But AD does not have to be parallel to BC

darkknight:

Unless specifically stated in a problem you can't make an assumption like that, so that is the correct reasoning, angles opposite in a quadrilateral inscribed in a circle are supplementary which you then use to prove

extrinix wrote:
now the only choice for \(\angle A\) is this: now we can create the equation for \(\angle A + \angle C = 180\) this would be, \((x+16)+(6x-4) = 180\) so, answer choice 1 would be your answer.

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