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A right square pyramid has a volume of 48 cm3 and a height of 4 cm. What is the slant height?

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Please help...

A right square pyramid has a volume of 48 cm3 and a height of 4 cm.  What is the slant height?

briannamilcic · Answer

it would be 7,680 for the slant height

briannamilcic · Answer

how though you can dm if you want

reds · Answer

that's too high to be the slant height how did you get that..?

reds · Answer

that's too high to be the slant height how did you get that..?

briannamilcic · Answer

my dad told me

jhonyy9 · Answer

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given that is a square pyramid what mean that the base is a square 
volume V = area of base B time height h divide 3

48 = B × h /3

B = side × side

h = 3

48 = B × 3/3

48 = B ×1

B = 48

(side)^2 = 48

side = sqrt48

side = sqrt(16*3)

side = 4sqrt3

side/2 = 4sqrt3 /2

side/2 = 2sqrt3

jhonyy9 · Answer

from triangle VOF with VO = 3 ,OF = 2sqrt3 using Pythagora's theorem you can calcule easy the length of slant height

jhonyy9 · Answer

sorry i made a mistaque height length is 4 not 3

@jhonyy9 wrote:

Created with Raphaëlslant heighthABCDOVFReply Using Drawing given that is a square pyramid what mean that the base is a square volume V = area of base B time height h divide 3 48 = B × h /3 B = side × side h = 4 48 = B × 4/3 48 ×3 = B ×4 B = 12 ×3 = 36 (side)^2 = 36 side = sqrt36 side = 6 side/2 = 6 /2 = 3 side/2 = 3

jhonyy9 · Answer

@jhonyy9 wrote:

from triangle VOF with VO = 3 ,OF = 2sqrt3 using Pythagora's theorem you can calcule easy the length of slant height

so in this way VO = 4 ,OF = 3 and now using these values you can calcule the length of slant height with Pythagora's theorem