A juice can is 16cm tall and has a diameter of 9cm. The ends of the can are tin and the body is cardboard.

a) What is the volume of the can?
b) What area of tin is used?
c) What area of cardboard is used?
d) What is the total area surface?

Question

A juice can is 16cm tall and has a diameter of 9cm. The ends of the can are tin and the body is cardboard.

a) What is the volume of the can?
b) What area of tin is used?
c) What area of cardboard is used?
d) What is the total area surface?

xHrishikx · Answer

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KIllerwolfdaone · Answer

this might help but let me tell you for the base it says diameter so it is cut in half and for the base do pi,r,^2

snowflake0531 · Answer

Error, you have to find the area of both circle areas, so $$2\pi r^2$$ multiply your B value by 2

Because of this, your C value is also wrong, you can't just subtract it, when your B is wrong
And also, the better way to do it is to use the formula, $$ 2\pi r(h) $$ so $$9\pi(16)$$ is your answer for C

xHrishikx · Answer

im confused so the person who answered it c would be wrong? this is what I put in 
a) 1017.9cm3
b) 63.6cm²
c)  890.07cm 
d) 579.62cm2

Extrinix · Answer

Let the know it all answer that question.

Gucchi · Answer

@snowflake0531 wrote:

Error, you have to find the area of both circle areas, so $$2\pi r^2$$ multiply your B value by 2 Because of this, your C value is also wrong, you can't just subtract it, when your B is wrong And also, the better way to do it is to use the formula, $$ 2\pi r(h) $$ so $$9\pi(16)$$ is your answer for C

I thought it was A

xHrishikx · Answer

@extrinix  what would be c then I doubled B

xHrishikx · Answer

this is due in like 4 mins can someone help me

xHrishikx · Answer

for c I wrote this : there is 2 circles on the cylinder, so you would do 63.6×2 to get 127.2, then subtract that from the total volume, so: 1017.9 −127.2= 890.07cm

Gucchi · Answer

Volume= Area of base X Height=pi*radius^2 x height=(4.5)^2 x pi x 16=324pi

xHrishikx · Answer

that doesnt help what would C and D be

Gucchi · Answer

surface area of sides=area of cardboard=2pi*radius*height
find the numeric value yourself

Gucchi · Answer

thats c

xHrishikx · Answer

and d?

xHrishikx · Answer

I did c what would D be

Extrinix · Answer

@snowflake0531

Gucchi · Answer

total sufrace area=answer in part b+part c=area of sides + area of ends=2pi*radius*height+2(pi*radius^2)

snowflake0531 · Answer

@xhrishikx wrote:

for c I wrote this : there is 2 circles on the cylinder, so you would do 63.6×2 to get 127.2, then subtract that from the total volume, so: 1017.9 −127.2= 890.07cm

no read what i wrote above, you have to use your formula $$2pi r (h)$$ so just do 9pi times 16, use your calculator

xHrishikx · Answer

so that would be 452.389342

xHrishikx · Answer

which would make the answer to D 579.62cm2

snowflake0531 · Answer

For A and D just do what Extrinix wrote before, volume is base times height, so 16 times 9 D is $$ 2\pi r^2 + 2\pi r(9) $$ so $$2\pi (4.5)^2 + 9\pi (16) $$

@xhrishikx wrote:

which would make the answer to D 579.62cm2

yes

xHrishikx · Answer

could you show the work for C

snowflake0531 · Answer

@xhrishikx wrote:

could you show the work for C

C is $$ 2\pi r(h) = 9\pi (16) $$ and then use a calculator

xHrishikx · Answer

okay thank you guys

surjithayer · Answer

a.
volume of can$$=\pi \times 4.5^2\times16 \approx 1017.9 ~cm^3$$

surjithayer · Answer

b.
$$area ~of~tin=\pi \times 4.5^2 \times 2 \approx 127.2 ~cm^2$$

surjithayer · Answer

c.
area of cardboard used$$=2pirh=2\pi \times 4.5\times 16=144 \pi \approx 452.4 ~cm^2$$

surjithayer · Answer

d.
total surface area
$$=2\pi rh+2 \pi r^2=2pir(h+r)=2\pi \times 4.5(16+4.5)=9\pi \times 20.5$$
$$=20.5\times9 \pi \approx 579.6 ~cm^2$$

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